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这是一个家庭作业问题（不要复制，复制不聪明）：我们需要使用 Verlet 方法在统一 2d 中绘制一个 2d 火鸡来更新顶点的位置。但是，我们不知道追踪土耳其的力量。这是土耳其的照片。有诀窍吗？ 在此处输入图像描述

这是我们开始的代码：

public class GenerateTurkeys : MonoBehaviour
{

    LineRenderer lineRenderer = gameObject.AddComponent<LineRenderer>();
    // Start is called before the first frame update
    int numberOfTurkeys;
    int NUM_PARTICLES;
    float fTimeStep;
    Vector3[] m_position = new Vector3[NUM_PARTICLES];
    Vector3[] m_acceleration = new Vector3[NUM_PARTICLES];
    Vector3[] m_oldPosition = new Vector3[NUM_PARTICLES];



    void Start()
    {
        NUM_PARTICLES = 100;
        numberOfTurkeys = 0;


    }
    // Verlet integration step void ParticleSystem::
    Verlet()
    {
        for (int i=0; i<NUM_PARTICLES; i++)
        {
            Vector3  x = m_position[i];
            Vector3 temp = x;
            Vector3 oldx = m_oldPosition[i];
            Vector3 a = m_acceleration[i];
            x += x-oldx+a* fTimeStep*fTimeStep;
            oldx = temp;
        }
    }
    void DrawLine(float[] heights)
    {

        LineRenderer lineRenderer = GetComponent<LineRenderer>();
        var t = Time.time;

        for (int i = 0; i < NUM_PARTICLES; i++)
        {

            lineRenderer.SetPosition(i, );
        }
    }

    // Update is called once per frame
    void Update()
    {

    }
}
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1 回答 1

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我不确定我的决定是否正确，因为轮廓不匹配，但在解决方案中，速度完全是迭代的。我认为这是 Unity 中物理的一个小错误，因为如果使用生成的加速度，可以非常准确地绘制图形。

在此处输入图像描述

这是代码：

public class Drawer : MonoBehaviour
{
    [SerializeField]
    private Transform[] m_Dots;

    private Rigidbody2D m_Dot;
    private Vector2[] m_Acceler;
    float deltaT = 0.5f;//for example

    private void Start()
    {
        m_Acceler = GetAcceler();

        var go = new GameObject("Tracer");
        var tr = go.AddComponent<TrailRenderer>();
        tr.widthMultiplier = 0.1f;
        tr.time = 50f;
        m_Dot = go.AddComponent<Rigidbody2D>();
        m_Dot.bodyType = RigidbodyType2D.Kinematic;
        m_Dot.gravityScale = 0;

        StartCoroutine(VerletCoroutine());
    }

    private Vector2[] GetAcceler()
    {
        Vector2[] result = new Vector2[m_Dots.Length];
        float T = deltaT;

        int len = m_Dots.Length;
        result[0] = An(m_Dots[1].position, m_Dots[0].position, m_Dots[0].position, T);
        for (int i = 1 ; i < len - 1 ; i++, T += deltaT)
        {
            result[i] = An(m_Dots[i + 1].position, m_Dots[i].position, m_Dots[i].position, T);
        }

        result[len - 1] = An(m_Dots[0].position, m_Dots[len - 1].position, m_Dots[len - 1].position, T);
        return result;
    }

    private Vector2 An(Vector2 Xnext, Vector2 Xn, Vector2 Xprev, float t)
    {// a[n] = (x[n+1] - 2*x[n]+x[n-1])/t^2
        return (Xnext - 2 * Xn + Xprev) / t * t;
    }

    private IEnumerator VerletCoroutine()
    {
        m_Dot.transform.position = m_Dots[0].position;
        Vector2 Vprev = Vector2.zero;
        int len = m_Acceler.Length - 1;
        float t = 0;
        int i = 0;
        while (true)
        {
            t += Time.deltaTime;
            if (t >= deltaT)
            {
                i++;
                if (i > len)
                {
                    break;
                }
                t = 0;
                Vprev = Vector2.zero;
            }
            Vprev = Vnext(Vprev, m_Acceler[i], m_Acceler[i], t);
            m_Dot.velocity = Vprev;
            yield return new WaitForEndOfFrame();
        }
        m_Dot.velocity = Vector3.zero;
        yield return null;
    }

    private Vector2 Vnext(Vector2 Vn, Vector2 Anext, Vector2 An, float t)
    {//v[n+1]= v[n]+0,5(a[n+1] +a[n]) * t
        var v = Vn + 0.5f * (Anext + An) * t;
        return v;
    }
}
于 2019-07-16T05:52:15.833 回答