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我正在尝试从 1000 页长的 PDF 中提取页面，但我只需要 [9,10,17,18,25,26,33,34,...等] 模式的页面。这些数字可以用以下公式表示：pg = 1/2 (7 - 3 (-1)^n + 8*n)。

我试图定义公式并插入，tabula.read_pdf但我不确定如何定义“n”变量，其中“n”的范围从 0 到 25。现在我将它定义为我认为是问题的列表。 .

n = list(range(25+1))
pg = 1/2 (7 - 3 (-1)^n + 8*n) 

df = tabula.read_pdf(path, pages = 'pg',index_col=0, multiple_tables=False)

尝试执行时，我得到一个 TypeError: 'int' object is not callable on line pg = 1/2 (7 - 3 (-1)^n + 8*n)。我将如何定义变量，以便表格提取符合公式条件的页面？

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1 回答 1

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公式是x = 1/2(8n - 3(-1)^n + 7)

步骤1：

pg = []  #Empty list to store the pages numbers calculated by formula
for i in range(1, 25+1):     # For 1000 pages pdf use 1000 instead of 25
    k = int(1/2*((8*n[i])-3*((-1)**n[i])+7))
    pg.append(k)

print(pg, end = '')  # This will give you list of page numbers

#[9, 10, 17, 18, 25, 26, 33, 34, 41, 42, 49, 50, 57, 58, 65, 66, 73, 74, 81, 82, 89, 90, 97, 98, 105]

第2步：

# Now run the loop through each of the pages with the table

df=pd.DataFrame([])
df_combine=pd.DataFrame([])

for pageiter in range(pg):
            df = tabula.read_pdf(path, pages=pageiter+1 ,index_col=0, multiple_tables=False, guess=False) #modify it as per your requirement
            df_combine=pd.concat([df,df_combine]) #you can choose between merge or concat as per your need

或者

df_data = []
for pageiter in range(pg):
            df = tabula.read_pdf(path, pages=pageiter+1 ,index_col=0, multiple_tables=False, guess=False) #modify it as per your requirement
            df_data.append(df)

df_combine= pd.concat(df_data, axis=1)

创建公式的参考链接 https://www.wolframalpha.com/widgets/view.jsp?id=a3af2e675c3bfae0f2ecce820c2bef43

于 2019-06-12T16:21:42.810 回答