当您使用 VLOOKUP 作为 WorksheetFunction 的成员时,错误将导致运行时错误。当您使用 VLOOKUP 作为 Application 的成员时,错误将导致返回值是错误,这可能会或可能不会导致运行时错误。我不知道为什么 MS 以这种方式设置它。
如果您使用 WorksheetFunction,您应该捕获错误。如果您使用 Application,您应该使用 Variant 变量并测试 IsError。这里有几个例子。
Sub VlookupWF()
Dim sUser As String
Dim sDrawn As String
Dim shSec As Worksheet
Dim shCon As Worksheet
Dim i As Long
Set shSec = ActiveWorkbook.Worksheets("sections")
Set shCon = ActiveWorkbook.Worksheets("consolidated")
For i = 2 To 2092
sUser = shCon.Cells(i, 1).Value
'initialize sDrawn
sDrawn = vbNullString
'trap the error when using worksheetfunction
On Error Resume Next
sDrawn = Application.WorksheetFunction.VLookup(sUser, shSec.Range("A2:B3865"), 2, False)
On Error GoTo 0
'see if sdrawn is still the initialized value
If Len(sDrawn) = 0 Then
sDrawn = "Not Found"
End If
shCon.Cells(i, 10).Value = sDrawn
Next i
End Sub
Sub VlookupApp()
Dim sUser As String
Dim vDrawn As Variant 'this can be a String or an Error
Dim shSec As Worksheet
Dim shCon As Worksheet
Dim i As Long
Set shSec = ActiveWorkbook.Worksheets("sections")
Set shCon = ActiveWorkbook.Worksheets("consolidated")
For i = 2 To 2092
sUser = shCon.Cells(i, 1).Value
vDrawn = Application.VLookup(sUser, shSec.Range("A2:B3865"), 2, False)
'see if vDrawn is an error
If IsError(vDrawn) Then
vDrawn = "Not Found"
End If
shCon.Cells(i, 10).Value = vDrawn
Next i
End Sub