我在 Inkscape 中制作了一个徽标。为了学习,我想通过 SVG 中的动画支持使徽标中的轮子形状旋转。
实现旋转很容易,但我很难指定正确的旋转轴。形状是一个齿轮,我希望它围绕它的中心旋转。反复试验得出 xy 坐标 (47.1275, 1004.17) (其分量奇怪地不对称,但我想这与 Inkscape 应用的变换矩阵有关)是一个很好的近似值(参见下面的 animateTransform 标签),但我将如何从第一原则得到?
<svg xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns="http://www.w3.org/2000/svg" version="1.1" xmlns:cc="http://creativecommons.org/ns#" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 321.281 150.799" xmlns:dc="http://purl.org/dc/elements/1.1/">
<g transform="translate(-9.9178912,-891.57237)">
<g transform="matrix(1.9522781,0,0,1.9522781,4.6434311,-1008.1558)">
<animateTransform attributeType="xml" attributeName="transform" type="rotate" from="0 47.1275 1004.17" to="45 47.1275 1004.17" dur="2s" fill="freeze" additive="sum" repeatCount="indefinite" />
<g transform="matrix(0.65043772,0,0,0.65043772,-143.67477,980.4256)" stroke="#666" stroke-miterlimit="4" stroke-dasharray="none" stroke-width="7.68713093" fill="none">
<path stroke-linejoin="miter" d="m293.404-3.51576c-2.73916,0-5.41514,0.287192-8,0.8125v6.1875c-3.47484,0.838872-6.7198,2.18462-9.6875,4l-4.375-4.375c-2.24264,1.48612-4.29226,3.22977-6.1875,5.125s-3.63888,3.94486-5.125,6.1875l4.375,4.375c-1.81538,2.9677-3.16112,6.21265-4,9.6875h-6.1875c-0.5253,2.58486-0.8125,5.26083-0.8125,8s0.2872,5.41515,0.8125,8h6.1875c0.83888,3.47485,2.18462,6.7198,4,9.6875l-4.375,4.375c1.48612,2.24264,3.22976,4.29227,5.125,6.1875s3.94486,3.63888,6.1875,5.125l4.375-4.375c2.9677,1.81538,6.21266,3.16113,9.6875,4v6.1875c2.58486,0.525308,5.26082,0.8125,8,0.8125,2.73916,0,5.41514-0.287192,8-0.8125v-6.1875c3.47484-0.838872,6.7198-2.18462,9.6875-4l4.375,4.375c2.24264-1.48612,4.29226-3.22977,6.1875-5.125s3.63888-3.94486,5.125-6.1875l-4.375-4.375c1.81538-2.9677,3.16112-6.21266,4-9.6875h6.1875c0.5253-2.58485,0.8125-5.26083,0.8125-8s-0.2872-5.41515-0.8125-8h-6.1875c-0.83888-3.47485-2.18462-6.7198-4-9.6875l4.375-4.375c-1.48612-2.24264-3.22976-4.29227-5.125-6.1875s-3.94486-3.63888-6.1875-5.125l-4.375,4.375c-2.9677-1.81538-6.21266-3.16113-9.6875-4v-6.1875c-2.58486-0.525308-5.26084-0.8125-8-0.8125z" stroke-dashoffset="162" stroke="#666" stroke-linecap="butt" stroke-miterlimit="4" stroke-dasharray="none" stroke-width="7.68713093" fill="none"/>
</g>
</g>
</g>
</svg>
根据我在规范中读到的内容,我会说应用的转换矩阵是
1.9522781 0 4.6434311
0 1.9522781 -1008.1558
0 0 1
和
0.65043772 0 -143.67477
0 0.65043772 980.4256
0 0 1
(-9.9178912,-891.57237,0)
它们是否在平移变换后应用于 xyz 坐标?
我想上面的正确分析会让我得到所描述路径的左上角,或者可能是第一个句柄的坐标。在那之后,是否必须解析路径来决定边界框,从而决定路径的中心(因为它涉及一个有点圆形的对象)?
不尝试在自由创建的形状上手动制作动画,这是一个教训吗?