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所以我们有一个实验室要做,它包括阅读文件和所有有趣的东西。

这是txt文件的样子:

Name0
22
1.2
Name1
22
2.71
Name2
19
3.51
Name3
18
3.91
Name4
20
1.6
Name5
19
1.03
Name6
18
3.78
Name7
19
3.19
Name8
18
2.37
Name9
21
1.01

我发布了应该尝试读取此信息的代码。谢谢你的时间!

我试过改变一些东西并用谷歌搜索异常但没有运气

    public void readFile()
    {
        //ran intill exception caught
        try
        {
            //finds the student.txt file to read using scanners
            Scanner s = new Scanner("Students.txt");

            while(s.hasNextLine())
            {
                //sets a string name to the first string (First text in 
students is name)
                String name = s.next();
                //looks for a line with a int value and then sets it to 
age
                int age = s.nextInt(); 
                //scans the next line for a double and sets it to gpa

                double gpa = s.nextDouble();
                //creates a new student object and passes what the file 
read into parameters
                Student studentOne = new Student(name , age, gpa);
                //adds new student to array list
                students.add(studentOne);
            }
            s.close();
        }
        // if an exception is caught it will print
        catch(Exception e)
        {
            System.out.println(e);
        }
    }

我相信它应该读取信息并将其存储在受尊重的类别中,因为我们知道它基于文本文件按此顺序排列,但是当我运行该方法时,我得到 java.util.NoSuchElementException

4

1 回答 1

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您收到NoSuchElementException是因为在对象上调用nextInt()andnextDouble()方法Scanner不会读取换行符(按回车时创建的字符) - 请参阅答案。

要解决此问题,您可以执行以下操作:

public void readFile() throws IOException {
    try (Scanner s = new Scanner(new FileReader(new ClassPathResource("Students.txt").getFile()))) {
        while (s.hasNextLine()) {
            String name = s.nextLine();
            int age = Integer.parseInt(s.nextLine());
            double gpa = Double.parseDouble(s.nextLine());
            Student studentOne = new Student(name, age, gpa);
            students.add(studentOne);
        }
    }
}

注意 - 上面的代码假定Students.txt文件在您的类路径中。

于 2019-05-25T18:05:33.013 回答