android - 以编程方式打开软键盘

Question

我有一个没有子小部件的活动，相应的 xml 文件是，

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/myLayout"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:focusable="true"
>
</LinearLayout>

我想在活动开始时以编程方式打开软键盘。我现在尝试的是，

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    InputMethodManager inputMethodManager = (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE);
    if (inputMethodManager != null) {
        inputMethodManager.toggleSoftInput(InputMethodManager.SHOW_FORCED, 0);
    }

给我一些指导。

score 155 · Accepted Answer

我已经使用以下几行在 onclick 事件中手动显示软键盘，并且键盘是可见的。

InputMethodManager inputMethodManager =
    (InputMethodManager)getSystemService(Context.INPUT_METHOD_SERVICE);
inputMethodManager.toggleSoftInputFromWindow(
    linearLayout.getApplicationWindowToken(),
    InputMethodManager.SHOW_FORCED, 0);

但是在活动打开时我仍然无法打开它，那么有什么解决方案吗？

score 126 · Accepted Answer

In your manifest file, try adding the following to the <activity> that you want to show the keyboard when the activity starts:

android:windowSoftInputMode="stateVisible"

This should cause the keyboard to become visible when the activity starts.

For more options, checkout the documentation.

score 39 · Accepted Answer

请按照下面的代码。我相信你的问题会得到解决。

if (imm != null){
        imm.toggleSoftInput(InputMethodManager.SHOW_FORCED,0);
   }

score 27 · Accepted Answer

这是作品

<activity
    ...
    android:windowSoftInputMode="stateVisible" >
</activity>

或者

getWindow().setSoftInputMode(WindowManager.LayoutParams.SOFT_INPUT_STATE_VISIBLE);

score 20 · Accepted Answer

我所需要的只是在一个非常精确的时刻露出键盘。这对我有用！谢谢贝尼特。

    private Handler mHandler= new Handler();

在非常精确的时刻：

    mHandler.post(
    new Runnable() {
        public void run() {
            InputMethodManager inputMethodManager =  (InputMethodManager)getSystemService(INPUT_METHOD_SERVICE);
            inputMethodManager.toggleSoftInputFromWindow(yourEditText.getApplicationWindowToken(), InputMethodManager.SHOW_FORCED, 0);
            yourEditText.requestFocus();
        }
    });

score 15 · Accepted Answer

我使用以下几行在 onclick 事件中手动显示软键盘。

public void showKeyboard(final EmojiconEditText ettext){
          ettext.requestFocus();
          ettext.postDelayed(new Runnable(){
            @Override public void run(){
              InputMethodManager keyboard=(InputMethodManager)getSystemService(Context.INPUT_METHOD_SERVICE);
              keyboard.showSoftInput(ettext,0);
            }
          }
        ,200);
        }

score 12 · Accepted Answer

把它放在 onResume 方法中：

findViewById(R.id.root_view_of_your_activity_layout).post(
new Runnable() {
    public void run() {
        InputMethodManager inputMethodManager =  (InputMethodManager)getSystemService(INPUT_METHOD_SERVICE);
        inputMethodManager.toggleSoftInputFromWindow(yourEditText.getApplicationWindowToken(),     InputMethodManager.SHOW_FORCED, 0);
        yourEditText.requestFocus();
    }
});

runnable 是必需的，因为当操作系统触发 onResume 方法时，您无法确定所有视图都在哪里绘制，因此从根布局调用的 post 方法使其等待每个视图都准备好。

score 10 · Accepted Answer

在活动的onCreate方法或片段的onActivityCreated中

....
view.getViewTreeObserver().addOnPreDrawListener(new ViewTreeObserver.OnPreDrawListener() {
        @Override
        public boolean onPreDraw() {
            view.removeOnPreDrawListener(this);
            InputMethodManager imm = (InputMethodManager) context.getSystemService(Context.INPUT_METHOD_SERVICE);
            imm.toggleSoftInput(InputMethodManager.SHOW_FORCED, 0);

            // !Pay attention to return `true`
            // Chet Haase told to 
            return true;
        }
    });

score 10 · Accepted Answer

科特林

fun hideKeyboard(activity: Activity) {
    val view = activity.currentFocus
    val methodManager = activity.getSystemService(Context.INPUT_METHOD_SERVICE) as InputMethodManager
    assert(view != null)
    methodManager.hideSoftInputFromWindow(view!!.windowToken, InputMethodManager.HIDE_NOT_ALWAYS)
}

private fun showKeyboard(activity: Activity) {
    val view = activity.currentFocus
    val methodManager = activity.getSystemService(Context.INPUT_METHOD_SERVICE) as InputMethodManager
    assert(view != null)
    methodManager.showSoftInput(view, InputMethodManager.SHOW_IMPLICIT)
}

爪哇

public static void hideKeyboard(Activity activity) {
    View view = activity.getCurrentFocus();
    InputMethodManager methodManager = (InputMethodManager) activity.getSystemService(Context.INPUT_METHOD_SERVICE);
    assert methodManager != null && view != null;
    methodManager.hideSoftInputFromWindow(view.getWindowToken(), InputMethodManager.HIDE_NOT_ALWAYS);
}

private static void showKeyboard(Activity activity) {
    View view = activity.getCurrentFocus();
    InputMethodManager methodManager = (InputMethodManager) activity.getSystemService(Context.INPUT_METHOD_SERVICE);
    assert methodManager != null && view != null;
    methodManager.showSoftInput(view, InputMethodManager.SHOW_IMPLICIT);
}

score 9 · Accepted Answer

好像这行得通

 protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_patientid);

        editText = (EditText)findViewById(R.id.selectPatient);
        //editText.requestFocus(); //works without that

    }

@Override
    protected void onResume() {

        findViewById(R.id.selectPatient).postDelayed(
        new Runnable() {
            public void run() {
                 editText.requestFocus();
                InputMethodManager inputMethodManager =  (InputMethodManager)getSystemService(Context.INPUT_METHOD_SERVICE);
                inputMethodManager.showSoftInput(editText,InputMethodManager.SHOW_IMPLICIT);
            }
        },100);
        super.onResume();
    }

似乎这效果更好：在清单中：

<application>
    <activity
        android:name="com.doodkin.myapp.ReportActivity"
        android:label="@string/title_activity_report"
        android:screenOrientation="sensor" 
        android:windowSoftInputMode="stateHidden" > // add this or stateVisible
    </activity>
</application>

似乎清单在 android 4.2.2 中工作但在 android 4.0.3 中不工作

score 7 · Accepted Answer

我用这样的方式以编程方式显示软键盘，这对我来说可以防止在启动键盘时自动调整屏幕大小。

在清单中：

<activity android:name="XXXActivity" android:windowSoftInputMode="adjustPan">
</activity>

在 XXX 活动中：

EditText et =  (EditText))findViewById(R.id.edit_text);  
  Timer timer = new Timer();
            TimerTask task = new TimerTask() {

                @Override
                public void run() {
                    InputMethodManager inputMethodManager=(InputMethodManager)getSystemService(Context.INPUT_METHOD_SERVICE);
                    inputMethodManager.toggleSoftInputFromWindow(et.getApplicationWindowToken(), InputMethodManager.SHOW_FORCED, 0);

                }
            };
            timer.schedule(task, 200);

我认为这将节省其他人搜索此问题的时间。

score 7 · Accepted Answer

我将它用作单身人士，例如：

public static void showSoftKeyboard(final Context context, final EditText editText) {
        try {
            editText.requestFocus();
            editText.postDelayed(
                    new Runnable() {
                        @Override
                        public void run() {
                            InputMethodManager keyboard = (InputMethodManager) context.getSystemService(Context.INPUT_METHOD_SERVICE);
                            keyboard.showSoftInput(editText, 0);
                        }
                    }
                    , 200);
        } catch (NullPointerException npe) {
            npe.printStackTrace();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

在您的活动中使用它，例如：

showSoftKeyboard(this, yourEditTextToFocus);

score 4 · Accepted Answer

这有效：

private static void showKeyboard(Activity activity) {
    View view = activity.getCurrentFocus();
    InputMethodManager imm = (InputMethodManager) activity.getSystemService(Context.INPUT_METHOD_SERVICE);
    imm.toggleSoftInput(InputMethodManager.SHOW_FORCED, 0);
}

你这样调用这个方法：

showKeyboard(NameOfActivity.this);

score 4 · Accepted Answer

InputMethodManager inputMethodManager=(InputMethodManager)getSystemService(Context.INPUT_METHOD_SERVICE);
            inputMethodManager.toggleSoftInput(InputMethodManager.SHOW_FORCED,0);

score 3 · Accepted Answer

getWindow().setSoftInputMode(WindowManager.LayoutParams.SOFT_INPUT_STATE_ALWAYS_VISIBLE);

在 onResume() 中使用上述代码打开软键盘

score 3 · Accepted Answer

public final class AAUtilKeyboard {

public static void openKeyboard(final Activity activity, final EditText editText) {
    final InputMethodManager imm = (InputMethodManager) activity.getSystemService(Context.INPUT_METHOD_SERVICE);
    if (imm != null) {
        imm.showSoftInput(editText, InputMethodManager.SHOW_IMPLICIT);
    }
}

public static void hideKeyboard(final Activity activity) {
    final View view = activity.getCurrentFocus();
    if (view != null) {
        final InputMethodManager imm = (InputMethodManager) activity.getSystemService(Context.INPUT_METHOD_SERVICE);
        if (imm != null) {
            imm.hideSoftInputFromWindow(view.getWindowToken(), 0);
        }
    }
}

score 3 · Accepted Answer

InputMethodManager.SHOW_FORCED 不是好的选择。如果您使用此设置，您应该管理隐藏键盘状态。我的建议是这样的；

    public void showSoftKeyboard(View view) {
    InputMethodManager inputMethodManager = (InputMethodManager) getActivity().getSystemService(Activity.INPUT_METHOD_SERVICE);
    view.requestFocus();
    inputMethodManager.toggleSoftInput(InputMethodManager.SHOW_IMPLICIT, 0);
}

此外，您可以专注于获取参数的视图（通常是 EditText）。这使它成为一个更有用的功能

有关 InputMethodManager.SHOW_IMPLICIT 和 SHOW_FORCED 的更多信息；输入法管理器

score 2 · Accepted Answer

类似于@ShimonDoodkin 的答案，这是我在片段中所做的。

https://stackoverflow.com/a/29229865/2413303

    passwordInput.postDelayed(new ShowKeyboard(), 300); //250 sometimes doesn't run if returning from LockScreen

ShowKeyboard在哪里

private class ShowKeyboard implements Runnable {
    @Override
    public void run() {
        passwordInput.setFocusableInTouchMode(true);
        passwordInput.requestFocus();            
        getActivity().getWindow().setSoftInputMode(WindowManager.LayoutParams.SOFT_INPUT_STATE_ALWAYS_VISIBLE);
        ((InputMethodManager) getActivity().getSystemService(Context.INPUT_METHOD_SERVICE)).showSoftInput(passwordInput, 0);
    }
}

成功输入后，我还要确保隐藏键盘

getActivity().getWindow().setSoftInputMode(WindowManager.LayoutParams.SOFT_INPUT_STATE_HIDDEN);
((InputMethodManager) getActivity().getSystemService(Context.INPUT_METHOD_SERVICE))
                    .hideSoftInputFromWindow(getView().getWindowToken(), 0);

score 2 · Accepted Answer

这是所需的源代码：

public static void openKeypad(final Context context, final View v) 
 {
new Handler().postDelayed(new Runnable() 
{
    @Override
    public void run() 
    {
        InputMethodManager inputManager =   (InputMethodManager)context.getSystemService(Context.INPUT_METHOD_SERVICE); 
        inputManager.showSoftInput(v, InputMethodManager.SHOW_IMPLICIT);    
        Log.e("openKeypad", "Inside Handler");
    }
},300);}

有关详细信息，请通过此链接。这对我有帮助。 https://github.com/Nikhillosalka/Keyboard/blob/master/README.md

score 2 · Accepted Answer

完美的工作代码来显示和隐藏edittextbox的软键盘.....

// code to hide soft keyboard
public void hideSoftKeyBoard(EditText editBox) {
     InputMethodManager imm = (InputMethodManager)getSystemService(Context.INPUT_METHOD_SERVICE);  
     imm.hideSoftInputFromWindow(editBox.getWindowToken(), 0);  
}




// code to show soft keyboard
private void showSoftKeyBoard(EditText editBox){
     InputMethodManager inputMethodManager = (InputMethodManager) this.getSystemService(Activity.INPUT_METHOD_SERVICE);
     editBox.requestFocus();
     inputMethodManager.toggleSoftInput(InputMethodManager.SHOW_FORCED, 0);
}

score 1 · Accepted Answer

已经有太多答案了，但除此之外没有什么对我有用

inputMethodManager.showSoftInput(emailET,InputMethodManager.SHOW_FORCED);

showSoftInput我用过SHOW_FORCED

我的活动有

 android:windowSoftInputMode="stateVisible|adjustResize"

希望这可以帮助某人

score 1 · Accepted Answer

我喜欢把它作为 Context 的扩展，所以你可以在任何地方调用它

fun Context.showKeyboard(editText: EditText) {
    val inputMethodManager: InputMethodManager =
        getSystemService(Context.INPUT_METHOD_SERVICE) as InputMethodManager
    inputMethodManager.toggleSoftInputFromWindow(
        editText.applicationWindowToken,
        InputMethodManager.SHOW_IMPLICIT, 0
    )
    editText.requestFocus()
    editText.setSelection(editText.text.length)
}

fun Context.hideKeyboard(editText: EditText) {
    val imm = getSystemService(Context.INPUT_METHOD_SERVICE) as InputMethodManager
    imm.hideSoftInputFromWindow(editText.windowToken, 0)
}

score 1 · Accepted Answer

将此方法发布到您的基础活动中，并将其用于其他活动，例如魅力

public void openKeyboard() {
    InputMethodManager imm =
            (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE);
    if (imm != null) {
        imm.toggleSoftInput(InputMethodManager.SHOW_FORCED, 0);
    }
}

score 1 · Accepted Answer

基于上述这样的答案，只要您有上下文，它就可以在KOTLIN中使用。

fun Context.showKeyboard(editText: EditText) {

    editText.requestFocus()
    editText.setSelection(editText.text.length)

    GlobalScope.launch {
        delay(200L)

        val inputMethodManager: InputMethodManager =
            getSystemService(Context.INPUT_METHOD_SERVICE) as InputMethodManager
        inputMethodManager.toggleSoftInputFromWindow(
            editText.applicationWindowToken,
            InputMethodManager.SHOW_IMPLICIT, 0
        )
    }
}

然后你可以在你的片段中调用它，例如如下

requireContext().showKeyboard(binding.myEditText)

score 1 · Accepted Answer

import androidx.core.view.WindowInsetsCompat.Type
import androidx.core.view.WindowInsetsControllerCompat

fun Activity.openKeyboard() {
    WindowInsetsControllerCompat(window, window.decorView).show(Type.ime())
}

fun Activity.hideKeyboard() {
    WindowInsetsControllerCompat(window, window.decorView).hide(Type.ime())
}

android - 以编程方式打开软键盘

25 回答 25

科特林

爪哇

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