我有一个讨厌的搜索问题。
有一个包含30000个对象和一个textView的结构数组,输入字母时,我删除空格并在searchText中设置文本,searchText有WillSet和DidSet,在WillSet中我取消所有旧文本的搜索任务并开始搜索新文本已设置。在search()
函数中,我遍历数组并向函数中的 DispatchWorkItem 添加逻辑,当我输入大量字符时anyTranslate()
,searchText 会出错。- [CFString length]: message sent to deallocated instance
我创建了一个test
不应该为真anyTranslate()
但有时打印为真的变量类型,只有当测试等于真时才会出现错误,据我所知DispatchWorkItem
不会一次取消所有任务,
我怎么解决这个问题?
static var splitArr = (first:[Words](),second:[Words](),third:[Words](), four:[Words](), five:[Words]()) // fragmented array for faster searching
var work:[DispatchWorkItem?] = [nil,nil,nil,nil,nil]
var test = false
private var searchText = "" {
didSet{
test = false
if searchText.count >= 2 {
self.search(nil)
}
}
willSet{
for (i,ind) in self.work.enumerated() {
ind?.cancel()
self.test = true
}
}
}
func search(_ completion:(() -> ())?){
update = true
words.removeAll()
DispatchQueue.main.async {
self.tableView.isUserInteractionEnabled = false
self.indicator.isHidden = false
self.indicator.startAnimating()
}
let arr = [ViewController.splitArr.first, ViewController.splitArr.second, ViewController.splitArr.third, ViewController.splitArr.four, ViewController.splitArr.five]
for (i,value) in arr.enumerated() {
work[i] = DispatchWorkItem { [weak self] in
let lang = Language.first()
for (index,words) in value.enumerated() {
guard self?.work[i]?.isCancelled == false else { break }
self?.anyTranslate(with: words, and: lang)
if index == value.count - 1 {
DispatchQueue.main.async {
if self?.words.count == 0 {
self?.noFound()
}
self?.tableView.reloadData()
self?.tableView.isUserInteractionEnabled = true
self?.indicator.isHidden = false
self?.indicator.stopAnimating()
completion?()
}
}
}
}
guard let current = work[i] else { return }
DispatchQueue.global(qos: .userInteractive).async(execute: current)
}
}
func anyTranslate(with words: Words, and lang:String){
let array = Language.getLang(lang: lang, word: words)
for value in array[0] ?? [""] {
if test == true {
print(true)
}
// - [CFString length]: message sent to deallocated instance
if value.hasPrefix(searchText) {
addWord(with: words)
return
}
}
}