node.js - Negating a backreference in regex

Question

I have written such regular expression:

(?<arg>(?<key>\w+)+=(?<quote>["'`])(?<value>(?:[^\k<quote>]|(?<=\\)\k<quote>)+\k<quote>))

but it doesn't work because of backreferencing inside [^]. I looked for solution on this thread and wrote this:

(?<arg>(?<key>\w+)+=(?<quote>["'`])(?<value>(?:(?!\k<quote>).|(?<=\\)\k<quote>)+\k<quote>))

however it still doesn't work.

What am I doing wrong?

I want to extract all keys with values from strings like:

arg="value" arg='value' arg=`value` arg="value 'value'" arg='value \'value\' value' arg="value \"value\" value" arg=`value \`value\ value`

regex101 - online preview

Answer 1

您可以使用正确的调和贪婪令牌来修复正则表达式：

(?<arg>               # Start arg group
  (?<key>\w+)         #  key group: 1+ word chars
  =                   # =
  (?<quote>['"`]?)    # quote group: an optional " ' or `
  (?<value>(?:(?!\k<quote>)[^\\])*(?:\\[\s\S](?:(?!\k<quote>)[^\\])*)*) # value group: any 0+ chars other than quote char with escaped quote chars allowed
  \k<quote>           # quote group value
)                     # end of arg group

请参阅正则表达式演示。

单线：

(?<arg>(?<key>\w+)=(?<quote>['"`]?)(?<value>(?:(?!\k<quote>)[^\\])*(?:\\[\s\S](?:(?!\k<quote>)[^\\])*)*)\k<quote>)

见演示。