该程序使用类并从文件中获取员工信息。我也提到了下面的文件。即使有错误，我也提到了我收到的输出。输出也有问题，但我认为这是因为它得到的信息错误。
运行此程序时，我收到以下错误消息：
Error: Run-Time Check Failure #2 - Stack around the variable 'info' was corrupted.
还有这个消息：
Unhandled exception at 0x00950A89 in employee.exe: Stack cookie instrumentation code detected a stack-based buffer overrun.
// 这个程序使用的文件是：
A.Smith 20001 25 40
T.Philip 20002 20 35
S.LOng 20003 15 50
G.Santos 20004 30 30
F.Farkas 20005 22 55
// 即使出现错误，运行后的输出是：
This week's employee history
Name Id Rate Hours
* A.Smith 20001 $25/h 40h
* T.Philip 20002 $20/h 35h
* S.LOng 20003 $15/h 50h
* G.Santos 20004 $30/h 30h
* F.Farkas 20005 $22/h 55h
This week's payment
Name Payment
* ╠╠╠╠╠╠╠╠ $0 <----------There is this error too
* T.Philip $700
* S.LOng $825
* G.Santos $900
* A.Smith $1000
* The average wages of the employees: $685.00
// 代码是：
/*
#include "pch.h"
#include <iostream>
#include <fstream>
#include <stdlib.h>
#include <string>
#include<iomanip>
*/
using namespace std;
struct records {
char name[50] = {};
char id[5] = {};
int rate = 0;
int hours = 0;
int pay = 0;
};
void take(records array[], const int a);
int calculator(records array[], const int a);
void swap(records array[], const int a);
double Average(records array[], int a);
ifstream infile;
int main()
{
const int n = 5;
这是第一次声明信息：
struct records info[n];
double averageWages;
int overTime = 0, i;
infile.open("Project 3.dat");
cout << "\n This week's employee history \n" << endl;
if (infile.is_open()) {
cout << " Name Id Rate Hours " << endl;
这里的函数使用结构的信息：
take(info, n);
cout << endl << endl;
cout << "This week's payment\n" << endl;
cout << " Name Payment" << endl;
这里还有其他功能使用信息：
calculator(info, n);
swap(info, n);
for (i = 0; i < n; i++) {
cout << "*" << setw(10) << info[i].name << setw(10) << "$" << info[i].pay << endl;
}
averageWages = Average(info, n);
cout << "\n\n" << "* The average wages of the employees: $" << averageWages << endl << endl;
}
else {
cerr << "Error! file cannot open." << endl;
exit(1);
}
return 0;
}
// 获取记录：
void take(records array[], const int a) {
for (int i = 0; i < a; i++) {
while (infile >> array[i].name >> array[i].id >> array[i].rate >> array[i].hours) {
cout << "*" << setw(9) << array[i].name << setw(10) << array[i].id << setw(10) << "$" << array[i].rate << "/h" << setw(10) << array[i].hours << "h " << endl;
}
} infile.close();
}
//交换记录以根据收到的总付款进行排列
void swap(records array[], const int a) {
bool tf; //true or false
do {
tf = false;
for (int i = 0; i < a; i++) {
if (array[i].pay > array[i + 1].pay) {
swap(array[i], array[i + 1]);
tf = true;
}
}
} while (tf);
records temp;
for (int i = 0; i < a - 1; ++i)
{
for (int j = i + 1; j < a; ++j)
{
if (array[i].pay > array[j].pay)
{
temp = array[i];
array[i] = array[j];
array[j] = temp;
}
}
}
}
To calculate average:
double Average(records array[], const int a) {
double total = 0;
double average;
for (int i = 0; i < a; i++) {
total = total + (array[i].pay);
average = total / a;
}
cout.setf(ios::fixed);
cout.setf(ios::showpoint);
cout.precision(2);
return (total / a);
}
// 计算工资：
int calculator(records array[], const int a) {
infile.open("Project 3.dat");
if (infile.is_open()) {
for (int i = 0; i < a; i++) {
infile >> array[i].name >> array[i].id >> array[i].rate >> array[i].hours;
if (array[i].hours > 40) {
int overTime = (array[i].hours - 40)*1.5;
array[i].pay = ((array[i].rate) * 40) + (overTime*(array[i].rate));
}
else {
array[i].pay = (array[i].rate)*(array[i].hours);
}
}
for (int i = 0; i < a; i++) {
return (array[i].pay);
}
}
}