5

最近我一直在开发一个聊天应用程序,但在异步加载聊天图像时遇到了麻烦。

使用 MessageKit - 2.0

我试过这个

import MessageKit

class Image: MediaItem {
  var url: URL?

  var image: UIImage?

  var placeholderImage: UIImage

  var size: CGSize

  init(url: URL) {
    self.url = url
    self.size = CGSize(width: 240, height: 240)
    self.placeholderImage = UIImage()
    DispatchQueue.global().async {
        if let data = try? Data(contentsOf: url) {
            if let image = UIImage(data: data) {
                DispatchQueue.main.async {
                    self.image = image
                }
            }
        }
    }
}

init(image: UIImage) {
    self.image = image
    self.size = CGSize(width: 240, height: 240)
    self.placeholderImage = UIImage()
}

}

MessageType然后我用初始化图像kind = .photo(Image(url: url))

这似乎不起作用。

4

1 回答 1

14

从那以后我了解到 MessageKit 在MessagesDisplayDelegate调用中提供了一个委托方法

func configureMediaMessageImageView(_ imageView: UIImageView,
                                    for message: MessageType,
                                    at indexPath: IndexPath,
                                    in messagesCollectionView: MessagesCollectionView)

我们可以使用此委托方法为给定消息异步加载图像。

我正在使用UIImageView扩展来帮助解决这个问题

import UIKit

extension UIImageView {
  func load(url: URL) {
    DispatchQueue.global().async { [weak self] in
        if let data = try? Data(contentsOf: url) {
            if let image = UIImage(data: data) {
                DispatchQueue.main.async {
                    self?.image = image
                }
            }
        }
     }
   }
 }

所以解决方法如下

func configureMediaMessageImageView(_ imageView: UIImageView,
                                    for message: MessageType,
                                    at indexPath: IndexPath,
                                    in messagesCollectionView: MessagesCollectionView) {
    /*acquire url for the image in my case i had a 
    custom type Message which stored  the image url */
    guard
        let msg = message as? Message,
        let url = msg.downloadURL
    else { return }
    imageView.load(url: url)
}
于 2019-01-03T07:29:59.533 回答