javascript - 使用firebase时如何防止离子刷新页面

Question

当用户每次单击按钮时，我都会创建一个计数器，它会从计数器中减去 1 更新 firebase 中的节点，然后通过另一种方法使用 .valuechanges.subscribe 返回此更改，但每次发生这种情况时，它都会刷新整个页面，删除所有用户输入。

constructor(private dd: PlayerInfoProvider, private strge: Storage, private ss: Slot2machineProvider, private slotProvider: SlotProvider) {
    this.slotProvider.getTries(this.dd.getCurrentUser()).valueChanges().subscribe(snapshot => this.gettries(snapshot));
  }

  gettries(snapshot) {

    // this.playerObject = snapshot;

    this.tries = snapshot;
  }

  runSlots() {

    if (this.tries <= 0) {

      alert("you cannot play anymore sorry!! but if you want you can purchase some more luck");
    } else {
      this.slotOne = Math.floor(Math.random() * 52) + 1;
      this.slotTwo = Math.floor(Math.random() * 52) + 1;
      this.slotThree = Math.floor(Math.random() * 52) + 1;
      this.slotFour = Math.floor(Math.random() * 52) + 1;
      this.slotFive = Math.floor(Math.random() * 52) + 1;

      // this.sloty1 = '<p > "' + this.slotOne + '"</p>';
      // this.sloty2 = '<p > "' + this.slotTwo + '"</p>';
      // this.sloty3 = '<p > "' + this.slotThree + '"</p>';
      // this.sloty4 = '<p > "' + this.slotFour + '"</p>';
      // this.sloty5 = '<p > "' + this.slotFive + '"</p>';

      if (this.slotOne !== this.slotTwo || this.slotTwo !== this.slotThree) {
        this.loggerr = "<h2>sorry try again.. </h2>";

        this.playerObject.tries = this.tries - 1;
        //alert("you only have " + this.playerObject.tries + " chances left ");

      //  this.ss.substractTries(this.dd.getCurrentUser(), this.playerObject);
      } else {
        this.loggerr = "<p>jackpot!!!</p>";
      }
    }
  }