1

如何自定义 Laravel ResourceCollection 元和链接信息。

链接仅包含 prev、next 和 self而不是默认情况下的 first、last、prev、next。

应包括分页信息,如:current_page、total_items、items_per_page、total_pages而不是 current_page、from、last_page、path、per_page、to、total。

这是元和链接信息现在在 JSON 响应中的样子:

"meta": {
    "currentPage": 2,
    "current_page": 1,
    "from": 1,
    "last_page": 3,
    "path": "http://localhost:8000/api",
    "per_page": 5,
    "to": 5,
    "total": 14
},
"links": {
    "self": "http://localhost:8000/api",
    "first": "http://localhost:8000/api?page=1",
    "last": "http://localhost:8000/api?page=3",
    "prev": null,
    "next": "http://localhost:8000/api?page=2"
}

..我希望它是这样的:

"meta": {
    "current_page": 1,
    "total_items": 15,
    "per_page": 5,
    "total_pages": 3
},
"links": {
    "prev": null,
    "next": "http://localhost:8000/api?page=2"
    "self": "http://localhost:8000/api",
}
4

1 回答 1

6

我不喜欢 Laravel 如何实现分页器和资源,因为它很难做某些事情,比如你提到的问题。

内件

在以您想要的方式自定义响应之前,您首先需要了解 ResourceCollections 如何转换为响应。

资源集合的原始toResponse方法如下所示:

public function toResponse($request)
{
    return $this->resource instanceof AbstractPaginator
                ? (new PaginatedResourceResponse($this))->toResponse($request)
                : parent::toResponse($request);
}

如果您进一步PaginatedResourceResponse查看课程,您将看到以下代码。

...
protected function paginationLinks($paginated)
{
    return [
        'first' => $paginated['first_page_url'] ?? null,
        'last' => $paginated['last_page_url'] ?? null,
        'prev' => $paginated['prev_page_url'] ?? null,
        'next' => $paginated['next_page_url'] ?? null,
    ];
}
...

protected function meta($paginated)
{
    return Arr::except($paginated, [
        'data', 
        'first_page_url',
        'last_page_url',
        'prev_page_url',
        'next_page_url',
    ]);
}

我建议阅读Illuminate\Http\Resources\Json\PaginatedResourceResponseIlluminate\Http\Resources\Json\ResourceResponse充分了解发生了什么。

解决方案 1:创建自定义 PaginatedResourceResponse

一种解决方案是创建一个扩展的新类PaginatedResourceResponse,并覆盖该paginationLinks方法。

所以它看起来像:

use Illuminate\Http\Resources\Json\PaginatedResourceResponse;

class CustomPaginatedResourceResponse extends PaginatedResourceResponse
{
    protected function paginationLinks($paginated)
    {
        return [
            'prev' => $paginated['prev_page_url'] ?? null,
            'next' => $paginated['next_page_url'] ?? null,
        ];
    }

    protected function meta($paginated)
    {
        $metaData = parent::meta($paginated);
        return [
            'current_page' => $metaData['current_page'] ?? null,
            'total_items' => $metaData['total'] ?? null,
            'per_page' => $metaData['per_page'] ?? null,
            'total_pages' => $metaData['total'] ?? null,
        ];
    }
}

然后你可以覆盖你的toResponse方法看起来像:

public function toResponse($request)
{
    return $this->resource instanceof AbstractPaginator
                ? (new CustomPaginatedResourceResponse($this))->toResponse($request)
                : parent::toResponse($request);
}

如果您想进一步自定义您的响应,您可以考虑覆盖覆盖其他方法。

toResponse解决方案 2:在 ResourceCollection 中覆盖

PaginatedResourceResponse您可以toResponse使用类似代码的轻量级版本覆盖 ResourceCollection 中的方法,而不是覆盖,如下所示:

public function toResponse($request)
{
    $data = $this->resolve($request);
    if ($data instanceof Collection) {
        $data = $data->all();
    }

    $paginated = $this->resource->toArray();
    // perform a dd($paginated) to see how $paginated looks like

    $json = array_merge_recursive(
        [
            self::$wrap => $data
        ],
        [
            'links' => [
                'first' => $paginated['first_page_url'] ?? null,
                'last' => $paginated['last_page_url'] ?? null,
                'prev' => $paginated['prev_page_url'] ?? null,
                'next' => $paginated['next_page_url'] ?? null,
            ],
            'meta' => [
                'current_page' => $metaData['current_page'] ?? null,
                'total_items' => $metaData['total'] ?? null,
                'per_page' => $metaData['per_page'] ?? null,
                'total_pages' => $metaData['total'] ?? null,
            ],
        ],
        $this->with($request),
        $this->additional
    );

    $status = $this->resource instanceof Model && $this->resource->wasRecentlyCreated ? 201 : 200;

    return response()->json($json, $status);
}

解决方案 3:覆盖withResponse方法

一个更简单但功能可能不太强大的选项是withResponse像这样覆盖资源集合中的 at :

public function withResponse($request, $response)
{
    $data = $response->getData(true);
    $prev = $data['links']['prev'];
    $next = $data['links']['next'];
    $self = $data['links']['self'];
    $data['links'] = compact('prev', 'next', 'self');
    $response->setData($data);
}
于 2018-11-22T23:18:33.297 回答