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I'm trying to code a Hill-RSA cryptography program that you can see a part of here:

q2=31
alphabet=["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z",","," ",".",";","_"]
X=np.zeros((m,1),dtype=np.int32)
Y=np.zeros((m,1),dtype=np.int32)
Texte_decode="";
for i in range(1,(len(Texte_code)/m)+1):
    for k in range(0,m):
        j=0
        while (Texte_code[k+m*(i-1)]<>alphabet[j+1]):
            j=j+1
        X[k]=j
    X=X.transpose()
    A2=np.zeros((m,m),dtype=np.int32)
    for u in range(0,m):
        for l in range(0,m):
            A2[u,l]=A[u,l]
    Y=X.dot(A2)
    Y=Y.transpose()
    pprint(Y)
    Y2=np.zeros((m,1),dtype=np.int32)
    for ind in range(0,m):
        Y2[ind]=Y[ind]%q2
    pprint(Y2)
    for k in range(0,m):
        Texte_decode=Texte_decode+alphabet[Y2[k]+1]
for i in range(len(Texte_decode),len(Texte_decode)-m+1,-1):
    if Texte_decode[i]=="." and Texte_decode[i-1]==".":
        Texte_decode=Texte_decode[1,i-1]
print Texte_decode

When i execute this part, I get

"TypeError: only integer scalar arrays can be converted to a scalar index"

on the line

Texte_decode=Texte_decode+alphabet[Y2[k]+1]

Can anyone help me get rid of this error?

Thanks in advance

4

1 回答 1

1

你做了什么调试？您是否审查了问题线元素的性质？

Texte_decode=Texte_decode+alphabet[Y2[k]+1]

k来自for k in range(0,m):所以这不应该是问题。这显然是一个整数。

您打印的Y2. 它被初始化为一个(m,1)数组。所以Y2[k]将是一个 (1,) 数组，对吧？

alphabet是一个列表。

在交互式 shell 中，让我们尝试一个测试用例：

In [70]: [1,2,3,4][np.array([1])]
---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-70-4ad73b219fa3> in <module>()
----> 1 [1,2,3,4][np.array([1])]

TypeError: only integer scalar arrays can be converted to a scalar index

同样的错误信息！

如果我们从一维数组开始，然后选择一个元素，则索引有效：

In [71]: [1,2,3,4][np.arange(4)[1]]
Out[71]: 2

现在我们了解了问题，解决方案应该很明显，对吧？

于 2018-11-20T17:34:24.277 回答