1

我有一个 CSV 文件，其中日期和时间分为 2 个字段。如何使用 FileHelpers 将 2 个字段聚合到相同的 DateTime 数据中？

谢谢，

2011.01.07,09:56,1.2985,1.2986,1.2979,1.2981,103
2011.01.07,09:57,1.2981,1.2982,1.2979,1.2982,75
2011.01.07,09:58,1.2982,1.2982,1.2976,1.2977,83
2011.01.07,09:59,1.2977,1.2981,1.2977,1.2980,97
2011.01.07,10:00,1.2980,1.2980,1.2978,1.2979,101
2011.01.07,10:01,1.2980,1.2981,1.2978,1.2978,57
2011.01.07,10:02,1.2978,1.2979,1.2977,1.2978,86
2011.01.07,10:03,1.2978,1.2978,1.2973,1.2973,84
2011.01.07,10:04,1.2973,1.2976,1.2973,1.2975,71
2011.01.07,10:05,1.2974,1.2977,1.2974,1.2977,53
2011.01.07,10:06,1.2977,1.2979,1.2976,1.2978,57
2011.01.07,10:07,1.2978,1.2978,1.2976,1.2976,53
2011.01.07,10:08,1.2976,1.2980,1.2976,1.2980,58
2011.01.07,10:09,1.2979,1.2985,1.2979,1.2980,63
4

3 回答 3

0

我回答我自己的问题。因为我的需求发生了变化，所以我并没有真正回答我自己的问题。我的问题已经演变为：我有一个 CSV 文件，其中日期和时间分为 2 个字段。如何使用 FileHelpers 将 2 个字段聚合到相同的 XLDate 数据中？

这是我使用此代码的完整项目： 在此处输入链接描述

        private void CreateGraphic(ZedGraphControl zgc)
    {
        // référence vers le "canevas"
        GraphPane pane = zgc.GraphPane;

        pane.Title.Text = "Japanese Candlestick Chart Demo";
        pane.XAxis.Title.Text = "Trading Date";
        pane.YAxis.Title.Text = "Share Price, $US";

        FileHelperEngine<MetaTrader4> engine = new FileHelperEngine<MetaTrader4>();

        engine.ErrorManager.ErrorMode = ErrorMode.SaveAndContinue;

        MetaTrader4[] res = engine.ReadFile(@"..\..\Data\EURUSD240.csv");

        if (engine.ErrorManager.ErrorCount > 0)
            engine.ErrorManager.SaveErrors("Errors.txt");

        StockPointList spl = new StockPointList();

        foreach (MetaTrader4 quotes in res)
        {
            DateTime dateTime = new DateTime();
            dateTime = DateTime.ParseExact(quotes.Date + "-" + quotes.Time, "yyyy.MM.dd-HH:mm",
                                             null);

            XDate xDate = new XDate(dateTime);
            StockPt pt = new StockPt(xDate, quotes.Hight, quotes.Low, quotes.Open, quotes.Close, quotes.Volume);
            spl.Add(pt);
        }

        JapaneseCandleStickItem myCurve = pane.AddJapaneseCandleStick("trades", spl);
        myCurve.Stick.IsAutoSize = true;
        myCurve.Stick.Color = Color.Blue;

        // Use DateAsOrdinal to skip weekend gaps
        pane.XAxis.Type = AxisType.DateAsOrdinal;

        // pretty it up a little
        pane.Chart.Fill = new Fill(Color.White, Color.LightGoldenrodYellow, 45.0f);
        pane.Fill = new Fill(Color.White, Color.FromArgb(220, 220, 255), 45.0f);

        zgc.AxisChange();

    }
于 2011-03-17T20:15:12.567 回答
0 
var file = @"2011.01.07,09:56,1.2985,1.2986,1.2979,1.2981,103
2011.01.08,09:57,1.2981,1.2982,1.2979,1.2982,75
2011.01.09,09:58,1.2982,1.2982,1.2976,1.2977,83
2011.01.07,09:59,1.2977,1.2981,1.2977,1.2980,97
2011.01.07,10:00,1.2980,1.2980,1.2978,1.2979,101
2011.01.07,10:01,1.2980,1.2981,1.2978,1.2978,57
2011.01.07,10:02,1.2978,1.2979,1.2977,1.2978,86
2011.01.07,10:03,1.2978,1.2978,1.2973,1.2973,84
2011.01.07,10:04,1.2973,1.2976,1.2973,1.2975,71
2011.01.07,10:05,1.2974,1.2977,1.2974,1.2977,53
2011.01.07,10:06,1.2977,1.2979,1.2976,1.2978,57
2011.01.07,10:07,1.2978,1.2978,1.2976,1.2976,53
2011.01.07,10:08,1.2976,1.2980,1.2976,1.2980,58
2011.01.07,10:09,1.2979,1.2985,1.2979,1.2980,63";

var rows = file.Split('\n');
foreach(var row in rows){
    var cols = row.Split(',');
    var col1 = new DateTime();
    foreach(var col in cols){
        if (col == cols[0]) // first col
        {
            var dateParts = col.Split('.');
            col1 = new DateTime(int.Parse(dateParts[0]), int.Parse(dateParts[1]), int.Parse(dateParts[2]));
        }
        else if (col == cols[1]) // second col
        {
            var timeParts = col.Split(':');
            col1 = col1.AddHours(int.Parse(timeParts[0]));
            col1 = col1.AddMinutes(int.Parse(timeParts[1]));
            //col1.Dump();
        }
        else {
                // all other columns here
            }
    }
}
于 2011-03-17T00:29:37.207 回答
0

您可以通过监听 engine.BeforeReadRecord 事件来做到这一点。

当您（引擎）读取每一行时，您需要删除日期和时间之间的分隔符，以使其符合您在 FieldConverter 属性中指定的预期日期时间格式。

这是一个 linqpad 片段来演示。

void Main()
{
    string reading = "2011.01.07,09:56,1.2985,1.2986,1.2979,1.2981,103";

    var engine = new FileHelperEngine<Reading>();

//engine.Options.Fields.Dump();

    char delimiter = ((DelimitedRecordOptions)engine.Options).Delimiter.ToCharArray().First();

    int expectedDelimiterCount = engine.Options.Fields.Sum(field => field.FieldType == typeof(DateTime) ? 2 : field.ArrayMinLength == 0 ? 1 : field.ArrayMinLength);

    expectedDelimiterCount--; // no ending delimiter

    engine.BeforeReadRecord += (ngin, e) => {

        int fieldCount = e.RecordLine.Count(c => c == delimiter);

        if (fieldCount == expectedDelimiterCount)
        {
            int delimiterIndex = e.RecordLine.IndexOf(delimiter);

            if (delimiterIndex > NOT_FOUND)
            {
                e.RecordLine = e.RecordLine.Remove(delimiterIndex, 1);          
            }
        }

    };


    var readings = engine.ReadString(reading);

    readings.Dump();

}

const int NOT_FOUND = -1;

// Define other methods and classes here
[DelimitedRecord(",")]
class Reading
{
    [FieldOrder(1)] 
    [FieldConverter(ConverterKind.Date, "yyyy.MM.ddHH:mm")]
    public DateTime CollectionDate { get; set; }

    [FieldOrder(2)] 
    [FieldArrayLength(4)]
    public decimal[] Data;

    [FieldOrder(3)] 
    public int CollectorID { get; set; }
}

将 DateTime 属性写到两个字段中作为练习留给读者。

于 2018-02-16T21:39:41.977 回答