1

我尝试从云功能发送命令，我收到错误：服务当前不可用。

Package.JSON“依赖项”：{“firebase-admin”：“~6.0.0”，“firebase-functions”：“^2.0.3”，“googleapis”：“34.0.0”}

const parentName = `projects/${projectId}/locations/${cloudRegion}`;
const registryName = `${parentName}/registries/${reqData.registryId}`;
const binaryData = Buffer.from(JSON.stringify(reqData.message)).toString('base64');
const request = {
    name: `${registryName}/devices/${reqData.deviceId}`,
    binaryData: binaryData
};

google.auth.getClient().then((authClient) => {
    const discoveryUrl =
        `${DISCOVERY_API}?version=${API_VERSION}`;
    if (authClient.createScopedRequired && authClient.createScopedRequired()) {
      // Scopes can be specified either as an array or as a single,
      // space-delimited string.
      authClient = authClient.createScoped([
        'https://www.googleapis.com/auth/cloud-platform'
      ]);
    }

    google.options({
      auth: authClient
    });

    google.discoverAPI(discoveryUrl).then((client, err) => {
      if (err) {
        console.log('Error during API discovery', err);
        return undefined;
      }
      client.projects.locations.registries.devices.sendCommandToDevice(request,
        (err, data) => {
          if (err) {
            console.log('Could not send command:', request);
            console.log('Message: ', err);
          } else {
            console.log('Success :', data.statusText);
          }
        });
    });
  });

日志：{ 错误：该服务当前不可用。在 createError (/user_code/node_modules/googleapis/node_modules/axios/lib/core/createError.js:16:15) 在结算 (/user_code/node_modules/googleapis/node_modules/axios/lib/core/settle.js:18: 12) 在 Unzip.emit (events.js: 185:7) 在 endReadableNT (_stream_readable.js:974:12) 在 _combinedTickCallback (internal/process/next_tick.js:80:11) 在 process._tickDomainCallback (internal/process/next_tick.js:128:9)

4

2 回答 2

2

问题是subfolder 必须指定，并且不能是空字符串。

当我在 Firebase 函数中使用它时，我只是将firebase子文件夹用于发送的任何没有特定子文件夹的命令

const request = {
    name: `${registryName}/devices/${deviceId}`,
    binaryData: Buffer.from(JSON.stringify(commandMessage)).toString("base64"),
    subfolder: 'firebase'
}

这是功能部门：

  "dependencies": {
    "firebase-admin": "^6.4.0",
    "firebase-functions": "^2.1.0",
    "fs-extra": "^7.0.0",
    "googleapis": "^36.0.0",
  },

这可能是由于

  1. 节点库中的错误
  2. 谷歌端点中的错误
  3. 谷歌缺乏测试

看来谷歌的“IoT”还很年轻，还需要做很多工作

于 2018-12-29T02:01:36.903 回答
1

我对 Firebase 云函数不太熟悉，但使用 Cloud Functions 的内联编辑器（https://console.cloud.google.com/functions）没有收到错误。你能告诉我你什么时候开始收到这个错误（如果你仍然遇到它）？

作为参考，这是我使用的代码（基本上是您所拥有的，但对projectId, cloudRegion.

const {google} = require('googleapis');

const API_VERSION = 'v1';
const DISCOVERY_API = 'https://cloudiot.googleapis.com/$discovery/rest';

exports.sendCommand = (req, res) => {
  let reqData = req.body;

  const projectId = reqData.projectId || process.env.GCLOUD_PROJECT;
  const cloudRegion = reqData.cloudRegion || process.env.GCLOUD_REGION;

  const parentName = `projects/${projectId}/locations/${cloudRegion}`;
  const registryName = `${parentName}/registries/${reqData.registryId}`;
  const binaryData = Buffer.from(JSON.stringify(reqData.message)).toString('base64');
  const request = {
      name: `${registryName}/devices/${reqData.deviceId}`,
      binaryData: binaryData
  };

  google.auth.getClient().then((authClient) => {
      const discoveryUrl =
          `${DISCOVERY_API}?version=${API_VERSION}`;
      if (authClient.createScopedRequired && authClient.createScopedRequired()) {
        // Scopes can be specified either as an array or as a single,
        // space-delimited string.
        authClient = authClient.createScoped([
          'https://www.googleapis.com/auth/cloud-platform'
        ]);
      }

      google.options({
        auth: authClient
      });

      google.discoverAPI(discoveryUrl).then((client, err) => {
        if (err) {
          console.log('Error during API discovery', err);
          return undefined;
        }
        client.projects.locations.registries.devices.sendCommandToDevice(request,
          (err, data) => {
            if (err) {
              console.log('Could not send command:', request);
              console.log('Message: ', err);
            } else {
              console.log('Success :', data.statusText);
            }
          });
      });
    });
  res.status(200).send(reqData.message);
};
于 2018-11-05T20:45:40.047 回答