4

尝试运行以下查询时，我收到此错误：“无法为不可为空的字段 User.first_name 返回 null。”。我不期待空结果。

Query:
{
  site(site_reference: 123456789) {
    site_name
    site_managers {
      _id
      first_name
    }
  }
}

我期望看到的是：

{
  "data": {
    "site": {
      "site_name": "Test Site",
      "site_managers": [
        {
          "_id": "5bbcd55ff7bd643be4d490fa",
          "first_name": "Claire"
        },
        {
          "_id": "5b9fa2e1f66fb32164f4d547",
          "first_name": "John"
        }
      ]
    }
  }
}

我的 MongoDB 将 _id 存储在一个可以返回的数组中，但是我的用户类型中的其他任何内容都返回 null。

用户架构：

type User {
    _id: String!,
    first_name: String!,
    last_name: String!,
    role_id: Int!
    email: String!,
    password: String,
    created_date: String!,
    updated_date: String!,
    last_login_date: String,
    reset_password_token: String
  }
  type Query {
    user(_id: String!): User!
    users(role_id: Int): [User!]!
  }

用户解析器：

  Query: {
    user: (parent, args) => User.findById(args._id),
    users: (parent, args) => {
      if (args.role_id) {
        return User.find({ role_id: args.role_id })
      }
      return User.find({})
    },
  },

网站架构：

  type Site {
    site_name: String!,
    use_policy: String!,
    redirect_url: String!,
    intro_text: String!,
    logo: String!,
    address_line_1: String!,
    address_line_2: String,
    address_city: String!,
    address_county: String!,
    address_postcode: String!,
    phone: String!,
    site_reference: Int!,
    site_managers: [User],
    business_id: String!,
    connect_duration: Int!,
    created_date: String!,
    updated_date: String!,
  }

  type Query {
    site(site_reference: Int!): Site!
    sites(business_id: Int!): [Site!]!
  }

站点解析器：

  Query: {
    site: (parent, args) =>
      Site.findOne({ site_reference: args.site_reference }),
    sites: (parent, args) => Site.find({ business_id: args.business_id }),
  },

我想我需要在我的解析器中为站点查询做更多的事情，但我不确定到底是什么。我已经尝试过使用 mongoose.populate 但无济于事，我得到的最远的结果是使用 populate 方法返回一个空数组。

在此先感谢您的时间。

编辑：这是我的猫鼬模式

用户模式

const UserSchema = new mongoose.Schema({
  first_name: { type: String, required: true },
  last_name: { type: String, required: true },
  role_id: { type: Number, required: true },
  email: { type: String, required: true },
  password: { type: String },
  created_date: { type: Date, default: Date.now, required: true },
  updated_date: { type: Date, default: Date.now, required: true },
  last_login_date: { type: Date },
  reset_password_token: { type: String },
})

网站架构：

const SiteSchema = new mongoose.Schema({
  site_name: { type: String, required: true },
  use_policy: {
    type: String,
    required: true,
    default: config.defaultUsePolicy,
  },
  redirect_url: {
    type: String,
    required: true,
    default: config.defaultRedirect,
  },
  intro_text: {
    type: String,
    required: true,
    default: config.defaultIntroText,
  },
  logo: { type: String, required: true, default: config.defaultLogo },
  address_line_1: { type: String, required: true },
  address_line_2: String,
  address_city: { type: String, required: true },
  address_county: { type: String, required: true },
  address_postcode: { type: String, required: true },
  phone: { type: String, required: true },
  site_reference: { type: String, required: true },
  site_managers: {type:[mongoose.Schema.Types.ObjectId], required: true}
  business_id: { type: mongoose.Schema.Types.ObjectId, required: true },
  connect_duration: { type: Number, required: true, default: 0 },
  created_date: { type: Date, default: Date.now, required: true },
  updated_date: { type: Date, default: Date.now, required: true },
})
4

1 回答 1

2

如果您使用的是 MongoDB 和 mongoose，您将希望使用它populate来加入您的收藏。为此，在您的模式中，您要填充的字段不仅需要有一个类型，还需要一个ref属性来告诉 mongoose 使用哪个模型来填充该字段，例如：

// Note the actual ref should be whatever name you passed to mongoose.model
site_managers: [{type:mongoose.Schema.Types.ObjectId, ref: 'User'}]

现在，populate在解析器中使用：

site: (parent, { site_reference }) => {
  return Site.findOne({ site_reference }).populate('site_managers').exec()
}

有关更详细的示例，请参阅文档。

于 2018-10-12T22:04:38.670 回答