我正在使用 Koa 和 Typescript 编写网络应用程序。在 vscode 中,我遇到了不需要的代码格式:当我使用对象解构方法声明变量时,vscode 将其自动格式化为多行:
deleteUser: async (ctx: Context) => {
const {
body: { userId }
} = ctx;
await userService.deleteUser(userId);
}
在这种情况下,我希望它保留在一行中:
deleteUser: async (ctx: Context) => {
const { body: { userId } } = ctx;
await userService.deleteUser(userId);
}
我喜欢 vscode 如何处理我的代码格式,所以我不想禁用它。但是如果行长度小于 80 个字符,我想找到一种解决方法来禁用对象解构格式。
我应该使用什么规则来解决这个问题?我应该更改 vscode 规则还是 tslint 规则?
这是我的 .tslint 文件:
{
"rules": {
"class-name": true,
"comment-format": [true, "check-space"],
"indent": ["tabs"],
"one-line": [true, "check-open-brace", "check-whitespace"],
"no-var-keyword": true,
"quotemark": [true, "double", "avoid-escape"],
"semicolon": [true, "always", "ignore-bound-class-methods"],
"max-line-length": [true, 120],
"whitespace": [
true,
"check-branch",
"check-decl",
"check-operator",
"check-module",
"check-separator",
"check-type",
"check-preblock"
],
"typedef-whitespace": [
true,
{
"call-signature": "nospace",
"index-signature": "nospace",
"parameter": "nospace",
"property-declaration": "nospace",
"variable-declaration": "nospace"
},
{
"call-signature": "onespace",
"index-signature": "onespace",
"parameter": "onespace",
"property-declaration": "onespace",
"variable-declaration": "onespace"
}
],
"no-internal-module": true,
"no-trailing-whitespace": true,
"no-null-keyword": true,
"prefer-const": true,
"jsdoc-format": true
}
}