0

我需要一个 xml 来创建视图。拥有带有 xml 数据的表：tbl1（xml 数据）

我想对其进行查看，以便数据采用关系形式。xml的结构如下：

<persons>
<person>
<name>BLA1</name>
<parameters>
<param>
<key>KKK1</key>
<value>VVV1</value>
</param>
<param>
<key>KKK2</key>
<value>VVV2</value>
</param>
</parameters>
</person>
<person>
<name>BLA2</name>
<parameters>
<param>
<key>KKK21</key>
<value>VVV21</value>
</param>
<param>
<key>KKK22</key>
<value>VVV22</value>
</param>
<param>
<key>KKK23</key>
<value>VVV23</value>
</param>

</parameters>
</person>
</persons>

并且新表中所需的模型将是： (NAME, PARAMS) 其中 PARAMS 的形式应为 key=value;key=value;

即样本行将是：'BLA1''KKK1=VVV1;KKK2=VVV2;'

4

3 回答 3

1 
select name, listagg(key||'='||value, ';') params
from 
xmltable( '$doc/persons/person/parameters/param' passing 
 XMLPARSE(DOCUMENT '
<persons>
  <person>
    <name>BLA1</name>
    <parameters>
      <param>
        <key>KKK1</key>
        <value>VVV1</value>
      </param>
      <param>
        <key>KKK2</key>
        <value>VVV2</value>
      </param>
    </parameters>
  </person>
  <person>
    <name>BLA2</name>
    <parameters>
      <param>
      <key>KKK21</key>
      <value>VVV21</value>
      </param>
      <param>
        <key>KKK22</key>
        <value>VVV22</value>
      </param>
      <param>
        <key>KKK23</key>
        <value>VVV23</value>
      </param>
    </parameters>
  </person>
</persons>
') as "doc"
    COLUMNS "NAME"  VARCHAR(64)  PATH '../../name'
    ,       "KEY"   VARCHAR(64)  PATH './key'    
    ,       "VALUE" VARCHAR(64)  PATH './value'
    ) as x
group by name;
于 2018-10-03T18:17:01.007 回答
0

可能有一种方法可以在 xquery 中进行列表聚合，但我不是这方面的专家，这是我所能得到的

select  *
from 
xmltable( '$doc/persons/person' passing 
 XMLPARSE(DOCUMENT '<persons>
<person><name>BLA1</name><parameters>
<param><key>KKK1</key><value>VVV1</value></param>
<param><key>KKK2</key><value>VVV2</value></param></parameters></person>
<person><name>BLA2</name><parameters>
<param><key>KKK21</key><value>VVV21</value></param>
<param><key>KKK22</key><value>VVV22</value></param>
<param><key>KKK23</key><value>VVV23</value></param></parameters></person></persons>') as "doc"
    COLUMNS "NAME" VARCHAR(64)  PATH './name'
    ,       "PARAMS" VARCHAR(64)  PATH 'fn:string-join(./parameters/param/key,";")'    
    ,       "VALUES" VARCHAR(64)  PATH 'fn:string-join(./parameters/param/value,";")'       
    ) as x

返回

 NAME PARAMS            VALUES
 ---- ----------------- -----------------
 BLA1 KKK1;KKK2         VVV1;VVV2
 BLA2 KKK21;KKK22;KKK23 VVV21;VVV22;VVV23

我不确定如何将 PARAMS 和 VALUES 合并到 xquery 中的单个列中

于 2018-10-03T20:23:56.683 回答
0

作为记录，这就是您在视图中使用马克的答案的方式

create table tbl1 (datas xml) organize by row;
INSERT INTO tbl1 VALUES '<persons>
<person><name>BLA1</name><parameters>
<param><key>KKK1</key><value>VVV1</value></param>
<param><key>KKK2</key><value>VVV2</value></param></parameters></person>
<person><name>BLA2</name><parameters>
<param><key>KKK21</key><value>VVV21</value></param>
<param><key>KKK22</key><value>VVV22</value></param>
<param><key>KKK23</key><value>VVV23</value></param></parameters></person></persons>'
;

CREATE VIEW vw1 AS
select  NAME
,       listagg(key||'='||value, ';') params
from tbl1
, xmltable( '$doc/persons/person/parameters/param' passing datas as "doc"
    COLUMNS "NAME" VARCHAR(64)  PATH '../../name'
    ,       "KEY" VARCHAR(64)  PATH './key'    
    ,       "VALUE" VARCHAR(64)  PATH './value'     
    ) 
group by NAME
于 2018-10-03T20:30:38.283 回答