我有一个相当密集的散点图,我正在使用 R 'ggplot2' 构建,我想使用 'ggrepel' 标记点的子集。我的问题是我想在散点图中绘制所有点,但只用 ggrepel 标记一个子集,当我这样做时,ggrepel 在计算放置标签的位置时不会考虑图中的其他点,这会导致到与图上其他点重叠的标签(我不想标记)。
这是说明该问题的示例图。
# generate data:
library(data.table)
library(stringi)
set.seed(20180918)
dt = data.table(
name = stri_rand_strings(3000,length=6),
one = rnorm(n = 3000,mean = 0,sd = 1),
two = rnorm(n = 3000,mean = 0,sd = 1))
dt[, diff := one -two]
dt[, diff_cat := ifelse(one > 0 & two>0 & abs(diff)>1, "type_1",
ifelse(one<0 & two < 0 & abs(diff)>1, "type_2",
ifelse(two>0 & one<0 & abs(diff)>1, "type_3",
ifelse(two<0 & one>0 & abs(diff)>1, "type_4", "other"))))]
# make plot
ggplot(dt, aes(x=one,y=two,color=diff_cat))+
geom_point()
如果我只绘制我想要标记的点的子集,那么 ggrepel 能够以相对于其他点和标签的非重叠方式放置所有标签。
ggplot(dt[abs(diff)>2 & (!diff_cat %in% c("type_3","type_4","other"))],
aes(x=one,y=two,color=diff_cat))+
geom_point()+
geom_text_repel(data = dt[abs(diff)>2 & (!diff_cat %in% c("type_3","type_4","other"))],
aes(x=one,y=two,label=name))
但是,当我想同时绘制这个数据子集和原始数据时,我会得到带有标签的重叠点:
# now add labels to a subset of points on the plot
ggplot(dt, aes(x=one,y=two,color=diff_cat))+
geom_point()+
geom_text_repel(data = dt[abs(diff)>2 & (!diff_cat %in% c("type_3","type_4","other"))],
aes(x=one,y=two,label=name))
如何让点子集的标签不与原始数据中的点重叠?