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我有以下脚本:

SELECT * 
FROM (
          SELECT distinct web_product_source_id, recipe_id,  cos_score,
                row_number() over (partition by web_product_source_id order by cos_score desc) as rnk 
          FROM (
                    SELECT  web_product_source_id, recipe_id, max(cos_score) cos_score
                    FROM edw_sandbox.combined_with_product_details_ouput_cleaned
                    WHERE web_supercat_source_id = 'cookware'
                    GROUP BY 1,2
                ) a
    ) b
WHERE rnk <= 20
ORDER BY web_product_source_id, rnk;

我想在“WHERE”语句中添加一个 if else 语句。如果 web_product_source_id id 包含以下任何术语(“cookware”、“set”等...),我希望数据排名前 20 位或前 40 位

须藤代码:

if 'set' or 'cookware' in web_product_source_id id: pull top 40 ranks
else: pull top 20 ranks and cos_score >= .7
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