14

我使用 matStepper,当我将 selectedIndex 设置为 3 时,我无法使用下一个和上一个导航。我可以单击水平步进器中的 (1),然后像往常一样使用下一个/上一个。所有表格均有效,单击 (1) 后,我可以使用 1-7 中的下一个进行导航。

注意我有 this.selectedIndex = 3; 硬编码

<mat-horizontal-stepper #stepper
                        [linear]="true"
                        [selectedIndex]="this.selectedIndex"
                        (selectionChange)="selectionChange(stepper)">

  <mat-step [stepControl]="form1">
    <app-observer-information></app-observer-information>
  </mat-step>
...
  <mat-step [stepControl]="form7">
    <app-observer-agreement></app-observer-agreement>
  </mat-step>

</mat-horizontal-stepper>



export class ObservationStatementStepperComponent implements OnInit {

  @ViewChild('ObserverInformationComponent') public component1: ObserverInformationComponent;
  ..
  @ViewChild('ObserverAgreementComponent') public component7: ObserverAgreementComponent;

  public selectedIndex: number;

  constructor(private sorDataService: SorDataService) {

    this.selectedIndex = 3; // Number(sorDataService.selectedIndex);
  }

  public ngOnInit() {
  }

  public selectionChange(stepper) {

    this.sorDataService.synchronizeStepper(stepper.selectedIndex + 1);
  }

  /**
   * @see https://stackoverflow.com/questions/48498966/angular-material-stepper-component-for-each-step
   */
  get form1() {
    return this.component1 ? this.component1.form : null;
  }
  ...
  get form7() {
    return this.component7 ? this.component7.form : null;
  }
}

问题在 stackblitz 中重现

<mat-horizontal-stepper linear #stepper [selectedIndex]="1">

https://stackblitz.com/edit/angular-syml71?file=app/create-profile.component.html

4

3 回答 3

14

快速破解:

HTML:

<mat-vertical-stepper [linear]="true" #stepper>

TS:

 @ViewChild('stepper')
  stepper: MatStepper;
 
 nextClick(): void {
    this.stepper.linear = false;
    this.stepper.selectedIndex = ...;
    setTimeout(() => {
       this.stepper.linear = true;
    });
}

编辑:必须添加“setTimeout”,因为没有它就无法工作。似乎是我讨厌的疯狂黑客,但不幸的是没有其他选择。

于 2019-05-18T16:50:26.753 回答
0

要使其与 一起[linear]="true"使用,请使用具有延迟的setTimeout函数:0

setTimeout(() => {
  this.stepper.selectedIndex = ...;
});

参考:https ://github.com/angular/components/issues/8479#issuecomment-444063732

于 2020-01-06T20:11:49.543 回答
0

我知道这似乎是愚蠢的解决方案,但你可以使用stepper.next()

 @ViewChild('stepper')  stepper: MatStepper;
 selectedStepNumber = 2;
 ....
  ngAfterViewInit() {
      setTimeout(() => {
        for (let i = 0; i < this.selectedStepNumber; i++) {
          this.stepper.next();
        }
      }, 0);
    }

于 2021-09-30T13:34:23.100 回答