5

所以我正在使用 Lexik JWT Authentication Bundle (Symfony 2.6) 并使用以下代码成功创建了用户和令牌:

$userRegistration = new UserRegistration();
$userRegistration->setPassword($request->request->get('password'));
$userRegistration->setEmail($request->request->filter('email'));
$userRegistration->setName($request->request->filter('name'));

$token = $this->jwtManager->create($RegisteredUser);
return $this->responseProvider->ok((object) [
    'userId' => $RegisteredUser->getId(),
    'token' => $token
]);

回复 :

"data": {
    "userId": 24,
    "token": "eyJhbGciOiJSUzI1NiJ9.eyJyb2xlcyI6WyJST0xFX1VTRVIiXSwidXNlcm5hbWUiOiJqYWdhZHVAaHViaWktbmV0d29yay5jb20iLCJleHAiOjE1MzYxNTI0MDAsImlhdCI6MTUzNTU0NzYwMH0.B7gnfGdW1ijAIlo9xUI0DwkGaajQAQPBkRx4ChILXRNtpLdwgEl_9gvWdiidFbSXJseS8jslOfuAFUIWATmbNBoWVa3nc8SxkIrKI29xZuN6hB7R-63RH2BKsAVPsEjgTIJoqkkCrfrSum-_d3LEf36jcXqZb8M-GRKI477IwSDDwG_7YK5v0mu8N4TATXhN0tZGNYxp8Y27EI-g0Gmj9BIiobxnqVVoBWHN5J8d-UCrXRq94ifhEiQBxkG9r_eacMscB80n1VsiN2ouKH2kX-HRxRJmcgmydxvR7RcEW-P6koTxkaZJGO6mv7auSudTFlDENpwD4OD7gtn_wMUDS_OuN8WT7rZp8lwKY9f8J9fiGyq5J-8C_HmyjW-h8WhuJmTUaKhCZ-eLgDm4Vs2IQGYkHJEDFumnIZ607MAa1CW1ChAvurqvUqJ3G4TTN4wYqAHpSKz4y8SAMLjO91cedBPH6K5i9lh5htF-mW_htem7e5ornicU_djSccgHbxfXHQYTHCnqLp7-ONfl_p4nmhIEK0wcF0gkBXbIitzeTjy7C_uf_FV1sLPE5cY3PUP42DmHrG4PuXHLv_L1EjErkrpna7pChKA_TPeiZjqMcQoE70sZw8rr8KnRF2hpABdU_M2ZXOt_vF5-T8mLmKqs0LHxE089vVC3xsAh0mUr4FE"
} 

当我尝试使用jwtManager->decode方法在其他控制器中解码当前令牌时,问题就开始了:

$jwt = "eyJhbGciOiJSUzI1NiJ9.eyJyb2xlcyI6WyJST0xFX1VTRVIiXSwidXNlcm5hbWUiOiJqYWdhZHVAaHViaWktbmV0d29yay5jb20iLCJleHAiOjE1MzYxNTI0MDAsImlhdCI6MTUzNTU0NzYwMH0.B7gnfGdW1ijAIlo9xUI0DwkGaajQAQPBkRx4ChILXRNtpLdwgEl_9gvWdiidFbSXJseS8jslOfuAFUIWATmbNBoWVa3nc8SxkIrKI29xZuN6hB7R-63RH2BKsAVPsEjgTIJoqkkCrfrSum-_d3LEf36jcXqZb8M-GRKI477IwSDDwG_7YK5v0mu8N4TATXhN0tZGNYxp8Y27EI-g0Gmj9BIiobxnqVVoBWHN5J8d-UCrXRq94ifhEiQBxkG9r_eacMscB80n1VsiN2ouKH2kX-HRxRJmcgmydxvR7RcEW-P6koTxkaZJGO6mv7auSudTFlDENpwD4OD7gtn_wMUDS_OuN8WT7rZp8lwKY9f8J9fiGyq5J-8C_HmyjW-h8WhuJmTUaKhCZ-eLgDm4Vs2IQGYkHJEDFumnIZ607MAa1CW1ChAvurqvUqJ3G4TTN4wYqAHpSKz4y8SAMLjO91cedBPH6K5i9lh5htF-mW_htem7e5ornicU_djSccgHbxfXHQYTHCnqLp7-ONfl_p4nmhIEK0wcF0gkBXbIitzeTjy7C_uf_FV1sLPE5cY3PUP42DmHrG4PuXHLv_L1EjErkrpna7pChKA_TPeiZjqMcQoE70sZw8rr8KnRF2hpABdU_M2ZXOt_vF5-T8mLmKqs0LHxE089vVC3xsAh0mUr4FE";
$test = $this->jwtManager->decode($jwt);

但是JWTManager::decode()必须实现接口Symfony\Component\Security\Core\Authentication\Token\TokenInterface而不是期望给出的字符串。

我的目标只是从这个令牌中获取 userId,但找不到如何解码令牌的任何信息。有谁知道如何简单地解码令牌?

4

3 回答 3

18

在不使用 JWT 库的情况下手动从令牌中获取信息非常简单。

JWT 字符串由 3 部分组成:base64url 编码的标头和有效负载,两者都是 JSON“对象”,以及签名。所有 3 个部分由 . 分隔.

因此,您只需将令牌拆分为 3 个部分,在此处使用 完成explode,然后解码 base64url 编码的字符串 ( base64_decode),最后解码 JSON ( json_decode):

$token = "eyJhbGciOiJSUzI1NiJ9.eyJyb2xlcyI6WyJST0xFX1VTRVIiXSwidXNlcm5hbWUiOiJqYWdhZHVAaHViaWktbmV0d29yay5jb20iLCJleHAiOjE1MzYxNTI0MDAsImlhdCI6MTUzNTU0NzYwMH0.B7gnfGdW1ijAIlo9xUI0DwkGaajQAQPBkRx4ChILXRNtpLdwgEl_9gvWdiidFbSXJseS8jslOfuAFUIWATmbNBoWVa3nc8SxkIrKI29xZuN6hB7R-63RH2BKsAVPsEjgTIJoqkkCrfrSum-_d3LEf36jcXqZb8M-GRKI477IwSDDwG_7YK5v0mu8N4TATXhN0tZGNYxp8Y27EI-g0Gmj9BIiobxnqVVoBWHN5J8d-UCrXRq94ifhEiQBxkG9r_eacMscB80n1VsiN2ouKH2kX-HRxRJmcgmydxvR7RcEW-P6koTxkaZJGO6mv7auSudTFlDENpwD4OD7gtn_wMUDS_OuN8WT7rZp8lwKY9f8J9fiGyq5J-8C_HmyjW-h8WhuJmTUaKhCZ-eLgDm4Vs2IQGYkHJEDFumnIZ607MAa1CW1ChAvurqvUqJ3G4TTN4wYqAHpSKz4y8SAMLjO91cedBPH6K5i9lh5htF-mW_htem7e5ornicU_djSccgHbxfXHQYTHCnqLp7-ONfl_p4nmhIEK0wcF0gkBXbIitzeTjy7C_uf_FV1sLPE5cY3PUP42DmHrG4PuXHLv_L1EjErkrpna7pChKA_TPeiZjqMcQoE70sZw8rr8KnRF2hpABdU_M2ZXOt_vF5-T8mLmKqs0LHxE089vVC3xsAh0mUr4FE";

$tokenParts = explode(".", $token);  
$tokenHeader = base64_decode($tokenParts[0]);
$tokenPayload = base64_decode($tokenParts[1]);
$jwtHeader = json_decode($tokenHeader);
$jwtPayload = json_decode($tokenPayload);
print $jwtPayload->username;

在最后一行中,您有所需的信息。

您还可以在https://jwt.io上检查您的令牌,以查看有效负载中包含哪些字段。该网站上也有关于 JWT 的很好的介绍。

于 2018-08-31T07:45:40.000 回答
9

您可以为此使用 JWTEncoder 服务。服务名称是lexik_jwt_authentication.jws_provider.lcobucci

或者,如果您希望使用类命名服务Lexik\Bundle\JWTAuthenticationBundle\Encoder\JWTEncoderInterface

您正在寻找的方法是decode()

$jwtEncoder->decode($yourToken);

于 2018-08-31T08:00:23.443 回答
0

请在没有任何库的情况下找到我的代码。

function decodeJWTPayloadOnly($token){
        $tks = explode('.', $token);
        if (count($tks) != 3) {
            return null;
        }
        list($headb64, $bodyb64, $cryptob64) = $tks;
        $input=$bodyb64;
        $remainder = strlen($input) % 4;
        if ($remainder) {
            $padlen = 4 - $remainder;
            $input .= str_repeat('=', $padlen);
        }
        $input = (base64_decode(strtr($input, '-_', '+/')));

        if (version_compare(PHP_VERSION, '5.4.0', '>=') && !(defined('JSON_C_VERSION') && PHP_INT_SIZE > 4)) {
            $obj = json_decode($input, false, 512, JSON_BIGINT_AS_STRING);
        } else {
            $max_int_length = strlen((string) PHP_INT_MAX) - 1;
            $json_without_bigints = preg_replace('/:\s*(-?\d{'.$max_int_length.',})/', ': "$1"', $input);
            $obj = json_decode($json_without_bigints);
        }
        return $obj;
}
于 2021-07-06T14:58:24.520 回答