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我试图从具有相同名称但扩展名不同的文件夹中读取和写入文件=>从中提取数据=>重写。这是我的代码：

for header_name in glob.glob(os.path.join(folder_path, "*.json")):
    for nii_name in glob.glob(os.path.join(folder_path, "*.nii")):
        with open(header_name, "r") as f:
        nii_meta = json.load(f)
        add_stc = slicetime(header_name).tolist()
        nii_meta["SliceTiming"] = add_stc
    with open(header_name, 'w') as f:
        json.dump(nii_meta, f, indent=2)

我试着做检查：

    h_name = os.path.splitext(os.path.basename(header_name))[0]
    n_name = os.path.splitext(os.path.basename(nii_name))[0]
    if h_name == n_name:
        do smth with data form files

但没有成功文件的名称是 sub01_T1w.json, sub01_T1w.nii.gz, sub01_T1w1.json, sub01_T1w1.nii.gz ...

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1 回答 1

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我建议使用pathlib，它是 python 标准库中一个相对较新的部分，可以更轻松地处理路径和文件。使用它的解决方案可能如下所示：

from pathlib import Path

p = Path('parent/folder/of/my/files')
json_names = {f.stem for f in p.iterdir() if f.suffix == '.json'}
nii_names = {Path(f.stem).stem for f in p.iterdir() if f.suffixes == ['.nii', '.gz']}
for file_name in json_names & nii_names:
    json_path = p / (file_name + '.json')
    nii_path = p / (file_name + '.nii.gz')
    with open(json_path) as json_file, open(nii_path) as nii_file:
        ...  # do things with the files' contents

如果要写入它们，请记住open(json_path, 'w')在退出只读with块后重新打开目标。

于 2018-08-27T13:03:03.367 回答