fortran - 如何处理格式化整数输入中的空白

Question

我有这样的文件

1980  01  23 

1982  04  30
1983  05  22
1984        
1985  02  11

我尝试使用格式“（3I4）”读取数据

implicit none

integer, parameter :: FUnitIn = 10
character(len=255) :: FNameIn = "./test.txt"


integer :: FStatOpen, FStatRead
integer :: yyyy, mm, dd


open ( unit    = FUnitIn, &
       file    = trim(FNameIn), &
       access  = "sequential", &
       form    = "formatted", &
       status  = "old", &
       iostat  = FStatOpen)
if (FStatOpen /= 0) then ! ERROR
    stop
end if


do
    read (FUnitIn, "(3I4)", iostat=FStatRead) yyyy, mm, dd
    if (FStatRead /= 0) then
        exit
    else
        write (6, "(3I4)") yyyy, mm, dd
    end if
end do

我得到了三个零的空白行。是否有任何选项来处理空​​白输入？

Answer 1

如果您的唯一目标是跳过空行，您可以读取字符变量中的每一行，并检查其调整后的长度，类似于以下代码（请参阅变量record）。超越这个简单的实现需要你提供一些额外的信息来确定你想要得到什么行为。

implicit none

integer, parameter  :: FUnitIn = 10
character(len=255)  :: FNameIn = "./test.txt"


integer             :: FStatOpen, FStatRead
integer             :: yyyy, mm, dd
character(len=1023) :: record


open ( unit    = FUnitIn, &
    file    = trim(FNameIn), &
    access  = "sequential", &
    form    = "formatted", &
    status  = "old", &
    iostat  = FStatOpen)
if (FStatOpen /= 0) then ! ERROR
    stop
end if


do
    read (FUnitIn, "(3I4)", iostat=FStatRead) record
    if (FStatRead /= 0) then
        exit
    elseif ( len_trim(adjustl(record)) > 0 ) then
        read (record, *) yyyy, mm, dd            
        write (6, "(3I4)") yyyy, mm, dd
    end if
end do