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在此处输入图像描述

我正在使用 Ionic Side-Menu 应用程序。上图突出了我的问题。我希望在导航到该特定页面时更改菜单活动状态。当单击菜单项进行导航而不是其他任何地方进行导航时，菜单状态工作正常。

从主页单击“转到列表”时，我在主页中使用以下代码。

import { Component } from '@angular/core';
import { NavController } from 'ionic-angular';
import { ListPage } from '../list/list';

@Component({
  selector: 'page-home',
  templateUrl: 'home.html'
})
export class HomePage {

  listPage =  ListPage; 
  constructor(public navCtrl: NavController) {

  }

  goToList(){
    this.navCtrl.setRoot(this.listPage);
  }
}

app.component.ts

import { Component, ViewChild } from '@angular/core';
import { Nav, Platform } from 'ionic-angular';
import { StatusBar } from '@ionic-native/status-bar';
import { SplashScreen } from '@ionic-native/splash-screen';

import { HomePage } from '../pages/home/home';
import { ListPage } from '../pages/list/list';
import { GalleryPage } from '../pages/gallery/gallery';

@Component({
  templateUrl: 'app.html'
})
export class MyApp {
  @ViewChild(Nav) nav: Nav;

  rootPage: any = HomePage;
  activePage: any;

  pages: Array<{title: string, component: any}>;

  constructor(public platform: Platform, public statusBar: StatusBar, public splashScreen: SplashScreen) {
    this.initializeApp();

    // used for an example of ngFor and navigation
    this.pages = [
      { title: 'Home', component: HomePage },
      { title: 'List', component: ListPage },
      { title: 'Gallery', component: GalleryPage}
    ];

    this.activePage = this.pages[0];

  }

  initializeApp() {
    this.platform.ready().then(() => {
      // Okay, so the platform is ready and our plugins are available.
      // Here you can do any higher level native things you might need.
      this.statusBar.styleDefault();
      this.splashScreen.hide();
    });
  }

  openPage(page) {
    // Reset the content nav to have just this page
    // we wouldn't want the back button to show in this scenario
    this.nav.setRoot(page.component);
    this.activePage = page;
  }

  checkActive(page){
    return page === this.activePage;
  }
}

对此有什么帮助吗？

4

1 回答 1

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我能够自己找到答案，因此将其发布以供其他人将来参考。

在ngAfterViewInit()中添加了代码，它似乎可以工作。

每次页面状态更改时都会调用ngAfterViewInit() ，并且view.instance.constructor.name为您提供当前页面的构造函数名称，您可以简单地将其与菜单数组进行比较以找出您导航到的页面并简单地设置它到活动页面。

请参阅下面的完整代码

import { Component, ViewChild } from '@angular/core';
import { Nav, Platform } from 'ionic-angular';
import { StatusBar } from '@ionic-native/status-bar';
import { SplashScreen } from '@ionic-native/splash-screen';

import { HomePage } from '../pages/home/home';
import { ListPage } from '../pages/list/list';
import { GalleryPage } from '../pages/gallery/gallery';

@Component({
  templateUrl: 'app.html'
})
export class MyApp {
  @ViewChild(Nav) nav: Nav;

  rootPage: any = HomePage;
  activePage: any;

  pages: Array<{title: string, component: any, active: boolean}>;

  constructor(public platform: Platform, public statusBar: StatusBar, public splashScreen: SplashScreen) {
    this.initializeApp();

    // used for an example of ngFor and navigation
    this.pages = [
      { title: 'Home', component: HomePage, active: false },
      { title: 'List', component: ListPage, active: false },
      { title: 'Gallery', component: GalleryPage, active: false}
    ];

    this.activePage = this.pages[0];

  }

  ngAfterViewInit(){
    this.nav.viewDidEnter.subscribe((view) => {
      for(let i = 0 ; i < this.pages.length ; i++){
        if(this.pages[i].component.name == view.instance.constructor.name){
           this.activePage = this.pages[i];
           break;
        }
      }
    });
  }

  initializeApp() {
    this.platform.ready().then(() => {
      // Okay, so the platform is ready and our plugins are available.
      // Here you can do any higher level native things you might need.
      this.statusBar.styleDefault();
      this.splashScreen.hide();
    });
  }

  openPage(page) {
    // Reset the content nav to have just this page
    // we wouldn't want the back button to show in this scenario
    this.nav.setRoot(page.component);
    this.activePage = page;
  }

  checkActive(page){
    // console.log(page.title, this.activePage.title, page === this.activePage);
    return page === this.activePage;
  }
}

于 2018-07-07T04:45:32.467 回答