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我有以下类结构(我的实际实现的简化示例):

/* TestClass.hpp */
#pragma once

template <class Impl>
class CurRecTemplate {
protected:
    CurRecTemplate() {}
    ~CurRecTemplate() {}

    Impl& impl() { return static_cast<Impl&>(*this); }
    const Impl& impl() const { return static_cast<const Impl&>(*this); }
};

template <class Impl>
class BaseClass : public CurRecTemplate<Impl> {
public:
    BaseClass() { };

    template <class FuncType>
    double eval(const FuncType& func, double x) const
    {
        return this->impl().evalImplementation(func, x);
    }
};

class DerivedClass : public BaseClass<DerivedClass> {
public:
    template <class FuncType>
    double evalImplementation(const FuncType& f, double x) const
    {
        return f(x);
    };
};

接着

/* Source.cpp */
#include <pybind11/pybind11.h>
#include "TestClass.hpp"

namespace py = pybind11;

template<typename Impl>
void declare(py::module &m, const std::string& className) {
    using DeclareClass = BaseClass<Impl>;

    py::class_<DeclareClass, std::shared_ptr<DeclareClass>>(m, className.c_str())
        .def(py::init<>())
        .def("eval", &DeclareClass::eval);
}

PYBIND11_MODULE(PyBindTester, m) {
    declare<DerivedClass>(m, "DerivedClass");
}

我松散地基于这个问题PyBind11 Template Class of Many Types的答案。但是我得到的错误是:

C2783 'pybind11::class_> &pybind11::class_>::def(const char *,Func &&,const Extra &...)': 无法推断 'Func' 的模板参数 ...\source.cpp 10
C2672 'pybind11::class_>::def': 找不到匹配的重载函数 ...\source.cpp 12

它似乎与template <class FuncType>我无法在任何地方定义的第二个有关,因为func稍后将传入通用函数。有什么办法可以规避这个问题吗?

4

1 回答 1

1

eval必须是一个接受双精度并返回双精度(或可转换为双精度的类型)的函数,因此您可以使用&DeclareClass::eval<double(*)(double)>;专门化模板 或者更好地包含<functional>and<pybind11/functional.h>并且您可以完全删除模板并将evalastd::function<double(double)>作为其第一个参数。

更具体地说,我将重写如下

/* TestClass.hpp */
#pragma once
#include <functional>

template <class Impl>
class CurRecTemplate {
protected:
    CurRecTemplate() {}
    ~CurRecTemplate() {}

    Impl& impl() { return static_cast<Impl&>(*this); }
    const Impl& impl() const { return static_cast<const Impl&>(*this); }
};

template <class Impl>
class BaseClass : public CurRecTemplate<Impl> {
public:
    BaseClass() { };

    double eval(std::function<double(double)> func, double x) const
    {
        return this->impl().evalImplementation(func, x);
    }
};

class DerivedClass : public BaseClass<DerivedClass> {
public:
    double evalImplementation(std::function<double(double)> f, double x) const
    {
        return f(x);
    };
}; 

/* Source.cpp */
#include <pybind11/pybind11.h>
#include "TestClass.hpp"
#include <pybind11/functional.h>

namespace py = pybind11;

template<typename Impl>
void declare(py::module &m, const std::string& className) {
    using DeclareClass = BaseClass<Impl>;

    py::class_<DeclareClass, std::shared_ptr<DeclareClass>>(m, className.c_str())
        .def(py::init<>())
        .def("eval", &DeclareClass::eval);
}

PYBIND11_MODULE(Project1, m) {
    declare<DerivedClass>(m, "DerivedClass");
}
于 2018-06-27T10:01:15.317 回答