如果我在 trunk/ 下有 20 个目录,每个目录中有很多文件,并且只需要其中的 3 个目录,那么是否可以只在 trunk 下的这 3 个目录进行 Subversion 检出?
7 回答
事实上,多亏了对我的帖子的评论,看起来稀疏目录是要走的路。我相信以下应该做到这一点:
svn checkout --depth empty http://svnserver/trunk/proj
svn update --set-depth infinity proj/foo
svn update --set-depth infinity proj/bar
svn update --set-depth infinity proj/baz
或者,--depth immediates
不要在没有内容的情况下empty
签出文件和目录。trunk/proj
这样您就可以查看存储库中存在哪些目录。
正如@zigdon 的回答中提到的,您还可以进行非递归结帐。这是实现类似效果的一种较旧且不太灵活的方法:
svn checkout --non-recursive http://svnserver/trunk/proj
svn update trunk/foo
svn update trunk/bar
svn update trunk/baz
Subversion 1.5 引入了稀疏检出,这可能对您有用。从文档中:
...稀疏目录(或浅签出) ...允许您轻松签出工作副本 - 或工作副本的一部分 - 比完全递归更浅,可以自由引入以前忽略的文件和子目录晚点。
我编写了一个脚本来自动化复杂的稀疏结帐。
#!/usr/bin/env python
'''
This script makes a sparse checkout of an SVN tree in the current working directory.
Given a list of paths in an SVN repository, it will:
1. Checkout the common root directory
2. Update with depth=empty for intermediate directories
3. Update with depth=infinity for the leaf directories
'''
import os
import getpass
import pysvn
__author__ = "Karl Ostmo"
__date__ = "July 13, 2011"
# =============================================================================
# XXX The os.path.commonprefix() function does not behave as expected!
# See here: http://mail.python.org/pipermail/python-dev/2002-December/030947.html
# and here: http://nedbatchelder.com/blog/201003/whats_the_point_of_ospathcommonprefix.html
# and here (what ever happened?): http://bugs.python.org/issue400788
from itertools import takewhile
def allnamesequal(name):
return all(n==name[0] for n in name[1:])
def commonprefix(paths, sep='/'):
bydirectorylevels = zip(*[p.split(sep) for p in paths])
return sep.join(x[0] for x in takewhile(allnamesequal, bydirectorylevels))
# =============================================================================
def getSvnClient(options):
password = options.svn_password
if not password:
password = getpass.getpass('Enter SVN password for user "%s": ' % options.svn_username)
client = pysvn.Client()
client.callback_get_login = lambda realm, username, may_save: (True, options.svn_username, password, True)
return client
# =============================================================================
def sparse_update_with_feedback(client, new_update_path):
revision_list = client.update(new_update_path, depth=pysvn.depth.empty)
# =============================================================================
def sparse_checkout(options, client, repo_url, sparse_path, local_checkout_root):
path_segments = sparse_path.split(os.sep)
path_segments.reverse()
# Update the middle path segments
new_update_path = local_checkout_root
while len(path_segments) > 1:
path_segment = path_segments.pop()
new_update_path = os.path.join(new_update_path, path_segment)
sparse_update_with_feedback(client, new_update_path)
if options.verbose:
print "Added internal node:", path_segment
# Update the leaf path segment, fully-recursive
leaf_segment = path_segments.pop()
new_update_path = os.path.join(new_update_path, leaf_segment)
if options.verbose:
print "Will now update with 'recursive':", new_update_path
update_revision_list = client.update(new_update_path)
if options.verbose:
for revision in update_revision_list:
print "- Finished updating %s to revision: %d" % (new_update_path, revision.number)
# =============================================================================
def group_sparse_checkout(options, client, repo_url, sparse_path_list, local_checkout_root):
if not sparse_path_list:
print "Nothing to do!"
return
checkout_path = None
if len(sparse_path_list) > 1:
checkout_path = commonprefix(sparse_path_list)
else:
checkout_path = sparse_path_list[0].split(os.sep)[0]
root_checkout_url = os.path.join(repo_url, checkout_path).replace("\\", "/")
revision = client.checkout(root_checkout_url, local_checkout_root, depth=pysvn.depth.empty)
checkout_path_segments = checkout_path.split(os.sep)
for sparse_path in sparse_path_list:
# Remove the leading path segments
path_segments = sparse_path.split(os.sep)
start_segment_index = 0
for i, segment in enumerate(checkout_path_segments):
if segment == path_segments[i]:
start_segment_index += 1
else:
break
pruned_path = os.sep.join(path_segments[start_segment_index:])
sparse_checkout(options, client, repo_url, pruned_path, local_checkout_root)
# =============================================================================
if __name__ == "__main__":
from optparse import OptionParser
usage = """%prog [path2] [more paths...]"""
default_repo_url = "http://svn.example.com/MyRepository"
default_checkout_path = "sparse_trunk"
parser = OptionParser(usage)
parser.add_option("-r", "--repo_url", type="str", default=default_repo_url, dest="repo_url", help='Repository URL (default: "%s")' % default_repo_url)
parser.add_option("-l", "--local_path", type="str", default=default_checkout_path, dest="local_path", help='Local checkout path (default: "%s")' % default_checkout_path)
default_username = getpass.getuser()
parser.add_option("-u", "--username", type="str", default=default_username, dest="svn_username", help='SVN login username (default: "%s")' % default_username)
parser.add_option("-p", "--password", type="str", dest="svn_password", help="SVN login password")
parser.add_option("-v", "--verbose", action="store_true", default=False, dest="verbose", help="Verbose output")
(options, args) = parser.parse_args()
client = getSvnClient(options)
group_sparse_checkout(
options,
client,
options.repo_url,
map(os.path.relpath, args),
options.local_path)
或者对 /trunk 进行非递归检出,然后手动更新您需要的 3 个目录。
如果您已经拥有完整的本地副本,则可以使用--set-depth
命令删除不需要的子文件夹。
svn update --set-depth=exclude www
请参阅:http: //blogs.collab.net/subversion/sparse-directories-now-with-exclusion
该set-depth
命令支持多条路径。
更新根本地副本不会改变修改文件夹的深度。
要将文件夹恢复为递归检出,您可以--set-depth
再次使用无限参数。
svn update --set-depth=infinity www
有点。正如鲍比所说:
svn co file:///.../trunk/foo file:///.../trunk/bar file:///.../trunk/hum
将获得文件夹,但从颠覆的角度来看,您将获得单独的文件夹。您将不得不对每个子文件夹进行单独的提交和更新。
我不相信您可以签出部分树,然后将部分树作为单个实体使用。
没有任何特别有用的方式,不。您可以检查子树(如 Bobby Jack 的建议),但随后您将失去自动更新/提交它们的能力;要做到这一点,它们需要被放置在他们的共同父项下,并且一旦您签出共同父项,您就会下载该父项下的所有内容。非递归不是一个好的选择,因为您希望更新和提交是递归的。