2

我身边的另一个新手问题:) 我试图查找它，但在这种情况下我找不到任何有意义的东西。我有这段代码在正常情况下工作正常。

import automationhat
import bluetooth
import time
import sys
import telegram

bot = telegram.Bot(token='56915444444:AAEzP5jy-pMD3ZME0twxY5bXkxxxxxxxxxxxxxxxxxxd_U')


# Import Adafruit IO MQTT client.
from Adafruit_IO import MQTTClient


ADAFRUIT_IO_KEY      = '73c755488accccccc361a506f700000002ba'
ADAFRUIT_IO_USERNAME = 'flxxxxxxxx'


def connected(client):
    print('Connected to Adafruit IO!  Listening for LockReg changes...')
    # Subscribe to changes on a feed named LockReg.
    client.subscribe('LockReg')

def disconnected(client):
    print('Disconnected from Adafruit IO!')
    sys.exit(1)

def message(client, feed_id, payload, retain):
    print('Feed {0} received new value: {1}'.format(feed_id, payload))

client = MQTTClient(ADAFRUIT_IO_USERNAME, ADAFRUIT_IO_KEY)

# Setup the callback functions defined above.
client.on_connect    = connected
client.on_disconnect = disconnected
client.on_message    = message

PHONES = ['B0:xx:2D:x0:C9:xx', 'xx:8D:08:xx:C3:7C', 'xx:AB:37:EA:93:xx']

while True:

        print "Checking " + time.strftime("%a, %d %b %Y %H:%M:%S", time.gmtime())

        for device in PHONES:
                result = bluetooth.lookup_name(device, timeout=5)
                if (result != None):
                    # Connect to the Adafruit IO server.
            client.connect()
            print('Door unlocked. Nearby: %s (%s)' % (result, device))
                        client.publish('lock.reg', result)
                        automationhat.relay.one.on()
                        time.sleep(2)
                        automationhat.relay.one.off()
            bot.sendMessage(-26934xxxxx, result)
                        time.sleep(180)
                else:
                        print "User out of range"
                        print('Door locked: No Bluetooth device detected. ' )
        time.sleep(10)

我的 systemd lock.service 文件如下所示：

[Unit]
 Description=My Lock  Service
 After=multi-user.target

 [Service]
 Type=idle
 ExecStart=/usr/bin/python /home/pi/lockreg.py > /home/pi/lock.log 2>&1

 [Install]
 WantedBy=multi-user.target

但是，如果在初始启动时从 systemd 执行，我会收到以下错误消息：

pi@raspberrypi:~ $ systemctl status lock.service
● lock.service - My Lock  Service
   Loaded: loaded (/lib/systemd/system/lock.service; enabled; vendor preset: enabled)
   Active: failed (Result: exit-code) since Sat 2018-06-16 18:33:32 CEST; 29min ago
  Process: 492 ExecStart=/usr/bin/python /home/pi/lockreg.py > /home/pi/lock.log 2>&1 (
 Main PID: 492 (code=exited, status=1/FAILURE)

Jun 16 18:33:29 raspberrypi systemd[1]: Started My Lock  Service.
Jun 16 18:33:32 raspberrypi python[492]: Traceback (most recent call last):
Jun 16 18:33:32 raspberrypi python[492]:   File "/home/pi/lockreg.py", line 11, in <mod
Jun 16 18:33:32 raspberrypi python[492]:     import telegram
Jun 16 18:33:32 raspberrypi python[492]: ImportError: No module named telegram
Jun 16 18:33:32 raspberrypi systemd[1]: lock.service: Main process exited, code=exited,
Jun 16 18:33:32 raspberrypi systemd[1]: lock.service: Unit entered failed state.
Jun 16 18:33:32 raspberrypi systemd[1]: lock.service: Failed with result 'exit-code'.

从 systemd 执行时，不知何故无法访问 Telegram 模块。为什么？

谢谢P的一些提示。

4

1 回答 1

1

有几件事可能是错误的。

可能telegram只为用户安装，pi而不是为所有用户全局安装。检查/home/pi/.local/你是否可以在那里找到电报。

如果没有，您会希望该模块安装在系统范围的site-packages目录中。使用以下方法可以找到：

> python
Python 2.7.15 (default, May 11 2018, 15:54:10) 
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> [p for p in sys.path if p.endswith('site-packages')]
['/usr/local/lib/python2.7/site-packages']
>>>

（它可能会是一个不同的目录，因为我python住在/usr/local/bin.）

然后检查telegram是否安装为目录中的文件或子目录site-packages。

这也可能是权限问题。Systemd 正在以某个用户 ID 运行您的程序。检查该特定用户是否可以读取site-packages目录和子目录。telegram

编辑： Systemd可以两种模式运行；系统和用户。只有后者作为特定用户运行。我猜系统模式运行为root. 从您的lock.service文件位置，我推测您正在系统模式下使用 systemd。根据您的评论，电报仅为用户安装pi。所以python运行 asroot 不应该看到它，这正是你所经历的。

所以基本上你有两个选择：

  • 为所有用户安装telegram 。（运行安装为root。）
  • 以用户身份运行用户模式 ​​systemd pi。
于 2018-06-17T19:29:52.310 回答