php - 依赖注入在 PHP 中的正确方式 - Laravel

Question

我有一个如下的日志类，我想将下面的类注入我的控制器并制作日志：

日志.php

<?php

namespace App\Helpers;

use DB;


class Log {

    private $tableName;
    private $tableId;
    private $tableIdVal;
    private $step;
    private $status;
    private $error;

    public function __construct($logTableName, $logTableId, $logTableIdVal, $step, $status, $error = null) {

        $this->tableName = $logTableName;
        $this->tableId   = $logTableId;
        $this->tableIdVal= $logTableIdVal;
        $this->step      = $step;
        $this->status    = $status;
        $this->error     = $error;

    }

    protected function create() {

        DB::table($this->tableName)->insert(
            [
                $this->tableId  =>  $this->tableIdVal,
                'step'          =>  $this->step,
                'error'         =>  $this->error,
                'status'        =>  $this->status
            ]
        );
    }

}

测试控制器.php

<?php

namespace App\Http\Controllers;

use App\Helpers\{Load, Log};
use App\Models\{Post, Raw, RawDetail};

use DB;

class DetailsController extends Controller
{
    private $file;
    private $log;

    public function __construct($record, Log $logger) {

        $this->file = $record;
        $this->log  = $logger;
    }

public function process() {

        //make a log (is this correct?) I think $this->log will find a log method in this file, which does not exist.
        //I want to simple make a call to the constructor and then call create method on it.
        $this->log('raw_logs', 'raw_id', $this->file->id, Raw::STEP_1, Raw::STATUS_1);

如果我使用依赖注入，我应该怎么做？

我可以这样做：

$log = new Log($all-params-here);
$log->create();

但我想避免使用新的。

我想做的事。

$this->log($parameters)->create();

Answer 1

1. 你可以像@HtmHell 在评论中所说的那样做：$this->log->create(parameters);
2. 您创建方法链接例如：$this->log->setData($parameters)->create();