ios - 从 iOS 获取反向地理编码当前位置的最简单方法

Question

我从这里的另一个问题中看到：确定 iPhone 用户所在的国家/地区，可以获取 iPhone 用户所在的当前国家/地区。

这对于许多用途来说非常方便。但是，是否有可能更深入地从 iOS（如果有信息）推断出用户所在的州或城市？

我想如果不可能的话，下一步将是反向地理编码服务。但是，您甚至可以为您的应用程序雇用诸如反向地理编码服务之类的东西吗？

Answer 1

MKReverseGeocoder在 iOS 5 中已弃用，现在是CLGeocoder

- (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation {
   [self.locationManager stopUpdatingLocation];

   CLGeocoder * geoCoder = [[CLGeocoder alloc] init];
   [geoCoder reverseGeocodeLocation:newLocation completionHandler:^(NSArray *placemarks, NSError *error) {
       for (CLPlacemark * placemark in placemarks) {
           .... = [placemark locality];
        }    
    }];
}

Answer 2

CLGeocoder *geocoder = [[CLGeocoder alloc] init];

CLLocation *newLocation = [[CLLocation alloc]initWithLatitude:21.1700
                                                    longitude:72.8300];

[geocoder reverseGeocodeLocation:newLocation
               completionHandler:^(NSArray *placemarks, NSError *error) {

                   if (error) {
                       NSLog(@"Geocode failed with error: %@", error);
                       return;
                   }

                   if (placemarks && placemarks.count > 0)
                   {
                       CLPlacemark *placemark = placemarks[0];

                       NSDictionary *addressDictionary =
                       placemark.addressDictionary;

                       NSLog(@"%@ ", addressDictionary);
                       NSString *address = [addressDictionary
                                            objectForKey:(NSString *)kABPersonAddressStreetKey];
                       NSString *city = [addressDictionary
                                         objectForKey:(NSString *)kABPersonAddressCityKey];
                       NSString *state = [addressDictionary
                                          objectForKey:(NSString *)kABPersonAddressStateKey];
                       NSString *zip = [addressDictionary 
                                        objectForKey:(NSString *)kABPersonAddressZIPKey];


                       NSLog(@"%@ %@ %@ %@", address,city, state, zip);
                   }

               }];

结果

{

  City = Surat;
  Country = India;
  CountryCode = IN;
  FormattedAddressLines =     (
    Surat,
    Gujarat,
    India
);
Name = Surat;
State = Gujarat;
} 
2012-12-20 21:33:26.284 CurAddress[4110:11603] (null) Surat Gujarat (null)

Answer 3

我将从CLReverseGeocoder课堂开始。

这个 stackoverflow 问题获取当前城市，并且可能适合您的使用。

Answer 4

以下代码可以很容易地检索到完整的详细信息。

 [geocoder reverseGeocodeLocation:newLocation completionHandler:^(NSArray *placemarks, NSError *error) {
        if(placemarks.count){

        placeNameLabel.text = [placemarks[0] name];
        streetNumberLabel.text = [placemarks[0] subThoroughfare];
        streetLabel.text = [placemarks[0] thoroughfare];
        neighborhoodLabel.text = [placemarks[0] subLocality];
        cityLabel.text = [placemarks[0] locality];
        countyLabel.text = [placemarks[0] subAdministrativeArea];
        stateLabel.text = [placemarks[0] administrativeArea];    //or province 
        zipCodeLabel.text = [placemarks[0] postalCode];
        countryLabel.text = [placemarks[0] country];
        countryCodeLabel.text = [placemarks[0] ISOcountryCode];
        inlandWaterLabel.text = [placemarks[0] inlandWater];
        oceanLabel.text = [placemarks[0] ocean];
        areasOfInterestLabel.text = [placemarks[0] areasOfInterest[0]];
        }
    }];