73

Q.1 我想将此表单转换为 ajax，但我的 ajax 代码似乎缺少一些东西。提交时根本不做任何事情。

Q2。我还希望在选择文件而不等待提交时触发更改。

这里是 JS。

$('#imageUploadForm').on('submit',(function(e) {
    e.preventDefault()
    $.ajax({
        type:'POST',
        url: $(this).attr('action'),
        data:$(this).serialize(),
        cache:false
    });
}));

以及带有 php 的 HTML。

<form name="photo" id="imageUploadForm" enctype="multipart/form-data" action="<?php echo $_SERVER["PHP_SELF"];?>" method="post">
    <input type="file" style="widows:0; height:0" id="ImageBrowse" hidden="hidden" name="image" size="30"/>
    <input type="submit" name="upload" value="Upload" />
    <img width="100" style="border:#000; z-index:1;position: relative; border-width:2px; float:left" height="100px" src="<?php echo $upload_path.$large_image_name.$_SESSION['user_file_ext'];?>" id="thumbnail"/>
</form>
4

5 回答 5

112

首先在您的 ajax 调用中包含成功和错误功能，然后检查它是否给您错误或什么？

你的代码应该是这样的

$(document).ready(function (e) {
    $('#imageUploadForm').on('submit',(function(e) {
        e.preventDefault();
        var formData = new FormData(this);

        $.ajax({
            type:'POST',
            url: $(this).attr('action'),
            data:formData,
            cache:false,
            contentType: false,
            processData: false,
            success:function(data){
                console.log("success");
                console.log(data);
            },
            error: function(data){
                console.log("error");
                console.log(data);
            }
        });
    }));

    $("#ImageBrowse").on("change", function() {
        $("#imageUploadForm").submit();
    });
});
于 2013-12-09T03:23:31.330 回答
24

HTML 代码

<div class="rCol"> 
     <div id ="prv" style="height:auto; width:auto; float:left; margin-bottom: 28px; margin-left: 200px;"></div>
       </div>
    <div class="rCol" style="clear:both;">

    <label > Upload Photo : </label> 
    <input type="file" id="file" name='file' onChange=" return submitForm();">
    <input type="hidden" id="filecount" value='0'>

这是 Ajax 代码：

function submitForm() {

    var fcnt = $('#filecount').val();
    var fname = $('#filename').val();
    var imgclean = $('#file');
    if(fcnt<=5)
    {
    data = new FormData();
    data.append('file', $('#file')[0].files[0]);

    var imgname  =  $('input[type=file]').val();
     var size  =  $('#file')[0].files[0].size;

    var ext =  imgname.substr( (imgname.lastIndexOf('.') +1) );
    if(ext=='jpg' || ext=='jpeg' || ext=='png' || ext=='gif' || ext=='PNG' || ext=='JPG' || ext=='JPEG')
    {
     if(size<=1000000)
     {
    $.ajax({
      url: "<?php echo base_url() ?>/upload.php",
      type: "POST",
      data: data,
      enctype: 'multipart/form-data',
      processData: false,  // tell jQuery not to process the data
      contentType: false   // tell jQuery not to set contentType
    }).done(function(data) {
       if(data!='FILE_SIZE_ERROR' || data!='FILE_TYPE_ERROR' )
       {
        fcnt = parseInt(fcnt)+1;
        $('#filecount').val(fcnt);
        var img = '<div class="dialog" id ="img_'+fcnt+'" ><img src="<?php echo base_url() ?>/local_cdn/'+data+'"><a href="#" id="rmv_'+fcnt+'" onclick="return removeit('+fcnt+')" class="close-classic"></a></div><input type="hidden" id="name_'+fcnt+'" value="'+data+'">';
        $('#prv').append(img);
        if(fname!=='')
        {
          fname = fname+','+data;
        }else
        {
          fname = data;
        }
         $('#filename').val(fname);
          imgclean.replaceWith( imgclean = imgclean.clone( true ) );
       }
       else
       {
         imgclean.replaceWith( imgclean = imgclean.clone( true ) );
         alert('SORRY SIZE AND TYPE ISSUE');
       }

    });
    return false;
  }//end size
  else
  {
      imgclean.replaceWith( imgclean = imgclean.clone( true ) );//Its for reset the value of file type
    alert('Sorry File size exceeding from 1 Mb');
  }
  }//end FILETYPE
  else
  {
     imgclean.replaceWith( imgclean = imgclean.clone( true ) );
    alert('Sorry Only you can uplaod JPEG|JPG|PNG|GIF file type ');
  }
  }//end filecount
  else
  {    imgclean.replaceWith( imgclean = imgclean.clone( true ) );
     alert('You Can not Upload more than 6 Photos');
  }
}

这是PHP代码：

$filetype = array('jpeg','jpg','png','gif','PNG','JPEG','JPG');
   foreach ($_FILES as $key )
    {

          $name =time().$key['name'];

          $path='local_cdn/'.$name;
          $file_ext =  pathinfo($name, PATHINFO_EXTENSION);
          if(in_array(strtolower($file_ext), $filetype))
          {
            if($key['name']<1000000)
            {

             @move_uploaded_file($key['tmp_name'],$path);
             echo $name;

            }
           else
           {
               echo "FILE_SIZE_ERROR";
           }
        }
        else
        {
            echo "FILE_TYPE_ERROR";
        }// Its simple code.Its not with proper validation.

这里上传和预览部分完成。现在，如果你想从页面和文件夹中删除和删除图像，那么代码就在这里进行删除。阿贾克斯部分：

function removeit (arg) {
       var id  = arg;
       // GET FILE VALUE
       var fname = $('#filename').val();
       var fcnt = $('#filecount').val();
        // GET FILE VALUE

       $('#img_'+id).remove();
       $('#rmv_'+id).remove();
       $('#img_'+id).css('display','none');

        var dname  =  $('#name_'+id).val();
        fcnt = parseInt(fcnt)-1;
        $('#filecount').val(fcnt);
        var fname = fname.replace(dname, "");
        var fname = fname.replace(",,", "");
        $('#filename').val(fname);
        $.ajax({
          url: 'delete.php',
          type: 'POST',
          data:{'name':dname},
          success:function(a){
            console.log(a);
            }
        });
    }

这是 PHP 部分（delete.php）：

$path='local_cdn/'.$_POST['name'];

   if(@unlink($path))
   {
     echo "Success";
   }
   else
   {
     echo "Failed";
   }
于 2016-06-03T06:36:18.867 回答
2

您可以使用 jquery.form.js 插件通过 ajax 将图像上传到服务器。

http://malsup.com/jquery/form/

这是示例 jQuery ajax 图片上传脚本

(function() {
$('form').ajaxForm({
    beforeSubmit: function() {  
        //do validation here


    },

    beforeSend:function(){
       $('#loader').show();
       $('#image_upload').hide();
    },
    success: function(msg) {

        ///on success do some here
    }
}); })();

如果您有任何疑问，请在此处参考以下 ajax 图片上传教程

http://www.smarttutorials.net/ajax-image-upload-using-jquery-php-mysql/

于 2014-09-03T18:32:03.517 回答
0 
Image upload using ajax and check image format and upload max size   

<form class='form-horizontal' method="POST"  id='document_form' enctype="multipart/form-data">
                                    <div class='optionBox1'>
                                        <div class='row inviteInputWrap1 block1'>
                                            <div class='col-3'>
                                                <label class='col-form-label'>Name</label>
                                                <input type='text' class='form-control form-control-sm' name='name[]' id='name' Value=''>
                                            </div>
                                            <div class='col-3'>
                                                <label class='col-form-label'>File</label>
                                                <input type='file' class='form-control form-control-sm' name='file[]' id='file' Value=''>
                                            </div>
                                            <div class='col-3'>
                                                <span class='deleteInviteWrap1 remove1 d-none'>
                                                    <i class='fas fa-trash'></i>
                                                </span>
                                            </div>
                                        </div>
                                        <div class='row'>
                                             <div class='col-8 pl-3 pb-4 mt-4'>
                                                <span class='btn btn-info add1 pr-3'>+ Add More</span>
                                                 <button class='btn btn-primary'>Submit</button> 
                                            </div>
                                        </div>
                                    </div>
                                    </form>     
                                    
                                    </div>  
                      
    
      $.validator.setDefaults({
       submitHandler: function (form) 
         {
               $.ajax({
                    url : "action1.php",
                    type : "POST",
                    data : new FormData(form),
                    mimeType: "multipart/form-data",
                    contentType: false,
                    cache: false,
                    dataType:'json',
                    processData: false,
                    success: function(data)
                    {
                        if(data.status =='success')
                            {
                                 swal("Document has been successfully uploaded!", {
                                    icon: "success",
                                 });
                                 setTimeout(function(){
                                    window.location.reload(); 
                                },1200);
                            }
                            else
                            {
                                swal('Oh noes!', "Error in document upload. Please contact to administrator", "error");
                            }   
                    },
                    error:function(data)
                    {
                        swal ( "Ops!" ,  "error in document upload." ,  "error" );
                    }
                });
            }
      });
    
      $('#document_form').validate({
        rules: {
            "name[]": {
              required: true
          },
          "file[]": {
              required: true,
              extension: "jpg,jpeg,png,pdf,doc",
              filesize :2000000 
          }
        },
        messages: {
            "name[]": {
            required: "Please enter name"
          },
          "file[]": {
            required: "Please enter file",
            extension :'Please upload only jpg,jpeg,png,pdf,doc'
          }
        },
        errorElement: 'span',
        errorPlacement: function (error, element) {
          error.addClass('invalid-feedback');
          element.closest('.col-3').append(error);
        },
        highlight: function (element, errorClass, validClass) {
          $(element).addClass('is-invalid');
        },
        unhighlight: function (element, errorClass, validClass) {
          $(element).removeClass('is-invalid');
        }
      });
    
      $.validator.addMethod('filesize', function(value, element, param) {
         return this.optional(element) || (element.files[0].size <= param)
        }, 'File size must be less than 2 MB');
于 2021-02-12T08:56:45.713 回答
-1

这是使用 HTML5 和 jQuery 的简单方法：

1）包含两个JS文件

<script src="jslibs/jquery.js" type="text/javascript"></script>
<script src="jslibs/ajaxupload-min.js" type="text/javascript"></script>

2) 包含 CSS 以拥有酷炫的按钮

<link rel="stylesheet" href="css/baseTheme/style.css" type="text/css" media="all" />

3）创建DIV或SPAN

<div class="demo" > </div>

4) 在您的 HTML 页面中编写此代码

$('.demo').ajaxupload({
    url:'upload.php'
});

5) 创建您的upload.php 文件以使用PHP 代码上传数据。

您可以从这里下载所需的 JS 文件 这里是示例

它太酷了，太快了，太容易了！:)

于 2015-06-12T11:31:26.643 回答