我需要根据值在 Route53 中找到一条记录。我的 Route53 有 10,000 多条记录。Web 界面当前不支持按值搜索具有超过 2000 条记录的托管区域。因此,我必须求助于使用AWS Route53 CLI 的 list-resource-record-sets命令和--query
参数。此参数使用JMESPath来选择或过滤结果集。
所以,让我们看看我们正在使用的结果集。
$ aws route53 list-resource-record-sets --hosted-zone-id Z3RB47PQXVL6N2 --max-items 5 --profile myprofile
{
"NextToken": "eyJTdGFydFJlY29yZE5hbWUiOiBudWxsLCAiU3RhcnRSZWNvcmRJZGVudGlmaWVyIjogbnVsbCwgIlN0YXJ0UmVjb3JkVHlwZSI6IG51bGwsICJib3RvX3RydW5jYXRlX2Ftb3VudCI6IDV9",
"ResourceRecordSets": [
{
"ResourceRecords": [
{
"Value": "ns-1264.awsdns-30.org."
},
{
"Value": "ns-698.awsdns-23.net."
},
{
"Value": "ns-1798.awsdns-32.co.uk."
},
{
"Value": "ns-421.awsdns-52.com."
}
],
"Type": "NS",
"Name": "mydomain.com.",
"TTL": 300
},
{
"ResourceRecords": [
{
"Value": "ns-1264.awsdns-30.org. awsdns-hostmaster.amazon.com. 1 7200 900 1209600 86400"
}
],
"Type": "SOA",
"Name": "mydomain.com.",
"TTL": 300
},
{
"ResourceRecords": [
{
"Value": "12.23.34.45"
}
],
"Type": "A",
"Name": "abcdefg.mydomain.com.",
"TTL": 300
},
{
"ResourceRecords": [
{
"Value": "34.45.56.67"
}
],
"Type": "A",
"Name": "zyxwvut.mydomain.com.",
"TTL": 300
},
{
"ResourceRecords": [
{
"Value": "45.56.67.78"
}
],
"Type": "A",
"Name": "abcdxyz.mydomain.com.",
"TTL": 300
}
]
}
理想情况下,我需要找到ResourceRecordSets.Name
,但我绝对可以返回ResourceRecordSet
具有ResourceRecords.Value == 45.56.67.78
.
我失败的尝试
// My first attempt was to use filters on two levels, but this always returns an empty array
ResourceRecordSets[?Type == 'A'].ResourceRecords[?Value == '45.56.67.78'][]
[]
// Second attempt came after doing more research on JMESPath. I could not find any good examples using filters on two levels, so I do not filter on ResourceRecordSets
ResourceRecordSets[*].ResourceRecords[?Value == '45.56.67.78']
[
[],
[],
[
{
"Value": "45.56.67.78"
}
],
[],
[]
]
在桌子上敲了一会儿我的头后,我决定咨询专家。使用上面的示例,我如何利用 JMESPath 和 AWS Route53 CLI 为带有 的记录返回以下两个之一Value == 45.56.67.78
?
[
"Name": "abcdxyz.mydomain.com."
]
或者
{
"ResourceRecords": [
{
"Value": "45.56.67.78"
}
],
"Type": "A",
"Name": "abcdxyz.mydomain.com.",
"TTL": 300
}