我正在尝试输出在一个链接模板中创建的秘密,并将其作为参数引用到另一个模板中。测试场景:
{
"$schema": "https://schema.management.azure.com/schemas/2015-01-01/deploymentTemplate.json#",
"contentVersion": "1.0.0.0",
"parameters": {
"templateBaseUrl": {
"type": "string"
}
},
"variables": {
"deployment1url": "[concat(parameters('templateBaseUrl'), '/deployment1.json')]",
"deployment2url": "[concat(parameters('templateBaseUrl'), '/deployment2.json')]"
},
"resources": [
{
"apiVersion": "2017-08-01",
"name": "deployment1",
"dependsOn": [],
"type": "Microsoft.Resources/deployments",
"properties": {
"mode": "Incremental",
"templateLink": {
"uri": "[variables('deployment1url')]",
"contentVersion": "1.0.0.0"
},
"parameters": {}
}
},
{
"apiVersion": "2017-08-01",
"name": "deployment2",
"dependsOn": [],
"type": "Microsoft.Resources/deployments",
"properties": {
"mode": "Incremental",
"templateLink": {
"uri": "[variables('deployment2url')]",
"contentVersion": "1.0.0.0"
},
"parameters": {
"testInput2": {
"value": "[reference('deployment1').outputs.testOutput1.value]"
}
}
}
}
],
"outputs": {}
}
部署1:
{
"$schema": "https://schema.management.azure.com/schemas/2015-01-01/deploymentTemplate.json#",
"contentVersion": "1.0.0.0",
"parameters": {
},
"resources": [],
"outputs": {
"testOutput1": {
"type": "securestring",
"value": "thisisapassword"
}
}
}
部署2:
{
"$schema": "https://schema.management.azure.com/schemas/2015-01-01/deploymentTemplate.json#",
"contentVersion": "1.0.0.0",
"parameters": {
"testInput2": {
"type": "securestring"
}
},
"resources": [],
"outputs": {}
}
运行此方案会在 '34' 行和 '9' 列引发错误“无法处理资源 '/subscriptions//resourceGroups/testrg1/providers/Microsoft.Resources/deployments/deployment2' 的模板语言表达式。'语言表达式属性'value' 不存在,可用的属性是 'type'。'"
因此,如果我将引用参数更改为,安全字符串输出上的“.value”将不起作用
"testInput2": {
"value": "[reference('deployment1').outputs.testOutput1]"
}
the errors changes to 'Deployment template validation failed: 'The provided value for the template parameter 'testInput2' at line '5' and column '23' is not valid.'.'
Is it possible to achieve what I am doing?
Thanks in advance