我创建了一个简单的 android 应用程序来控制连接到我的 Raspberry Pi 的继电器。我已经使用按钮以及基本的语音识别来触发这些按钮并打开/关闭相应的中继通道。
到目前为止，语音识别部分由 RecognizerIntent 处理，其中我需要按下我的应用程序上的一个按钮来打开一个谷歌语音提示，它会听我的语音命令并激活/停用控制继电器开关的相应按钮。
我想对连续语音识别做同样的事情，它允许应用程序连续听我的命令，而用户不必按下应用程序上的按钮，从而允许免提操作。
这是我现有的代码，一种非常简单的语音识别方法，可以让我打开和关闭连接到继电器的各种设备的按钮：
public void micclick(View view) {
if(view.getId()==R.id.mic)
{promptSpeechInput();}
}
private void promptSpeechInput() {
Intent i= new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);
i.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL,RecognizerIntent.LANGUAGE_MODEL_FREE_FORM);
i.putExtra(RecognizerIntent.EXTRA_LANGUAGE, Locale.getDefault());
i.putExtra(RecognizerIntent.EXTRA_PROMPT,"Speak!");
try{
startActivityForResult(i,100);
}
catch (ActivityNotFoundException a)
{
Toast.makeText(MainActivity.this,"Sorry your device doesn't support",Toast.LENGTH_SHORT).show();
}
}
public void onActivityResult(int requestCode, int resultCode, Intent i) {
super.onActivityResult(requestCode, resultCode, i);
String voicetxt;
switch (requestCode) {
case 100:
if (resultCode == RESULT_OK && i != null) {
ArrayList<String> result2 = i.getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS);
voicetxt = result2.get(0);
if (voicetxt.equals("fan on")) {
StringBuffer result=new StringBuffer();
toggleButton1.setChecked(true);
result.append("Fan: ").append(toggleButton1.getText());
sc.onRelayNumber="a";
new Thread(sc).start();
Toast.makeText(MainActivity.this, result.toString(),Toast.LENGTH_SHORT).show();
}
if (voicetxt.equals("fan of")) {
StringBuffer result=new StringBuffer();
toggleButton1.setChecked(false);
result.append("Fan: ").append(toggleButton1.getText());
sc.onRelayNumber = "a_off";
new Thread(sc).start();
Toast.makeText(MainActivity.this, result.toString(),Toast.LENGTH_SHORT).show();
}
if (voicetxt.equals("light on")) {
StringBuffer result=new StringBuffer();
toggleButton2.setChecked(true);
result.append("Light: ").append(toggleButton2.getText());
sc.onRelayNumber = "b";
new Thread(sc).start();
Toast.makeText(MainActivity.this, result.toString(),Toast.LENGTH_SHORT).show();
}
if (voicetxt.equals("light off")) {
StringBuffer result=new StringBuffer();
toggleButton2.setChecked(false);
result.append("Light: ").append(toggleButton2.getText());
sc.onRelayNumber = "b_off";
new Thread(sc).start();
Toast.makeText(MainActivity.this, result.toString(),Toast.LENGTH_SHORT).show();
}
if (voicetxt.equals("air conditioner on")) {
StringBuffer result=new StringBuffer();
toggleButton3.setChecked(true);
result.append("AC: ").append(toggleButton3.getText());
sc.onRelayNumber = "c";
new Thread(sc).start();
Toast.makeText(MainActivity.this, result.toString(),Toast.LENGTH_SHORT).show();
}
if (voicetxt.equals("air conditioner of")) {
StringBuffer result=new StringBuffer();
toggleButton3.setChecked(false);
result.append("AC: ").append(toggleButton3.getText());
sc.onRelayNumber = "c_off";
new Thread(sc).start();
Toast.makeText(MainActivity.this, result.toString(),Toast.LENGTH_SHORT).show();
}
if (voicetxt.equals("heater on")) {
StringBuffer result=new StringBuffer();
toggleButton4.setChecked(true);
result.append("Heater: ").append(toggleButton4.getText());
sc.onRelayNumber = "d";
new Thread(sc).start();
Toast.makeText(MainActivity.this, result.toString(),Toast.LENGTH_SHORT).show();
}
if (voicetxt.equals("heater off")) {
StringBuffer result=new StringBuffer();
toggleButton4.setChecked(false);
result.append("Heater: ").append(toggleButton4.getText());
sc.onRelayNumber = "d_off";
new Thread(sc).start();
Toast.makeText(MainActivity.this, result.toString(),Toast.LENGTH_SHORT).show();
}
}
break;
}
}
我想实现相同的功能而不必按下按钮。请注意，我是 Android 应用程序开发的新手。如果可能，请描述外部库的使用，如果需要的话，因为我认为谷歌的 RecognizerIntent 不可能进行连续识别。我推测我可能需要包含像CMUSphinx这样的库，但我不确定如何去做。