iphone - 如何将值插入到我的 sqlite3 数据库表中？

Question

我正在编写一个简单的查询，如下所示

const char *sql = "插入 abc(name) 值 ('Royal')";

这将每次将“皇家”插入到我的“姓名”中，所以现在我想每次都将用户的输入作为酒店的名称，并希望保存它们而不是“皇家”，那我该怎么办？

如果您对我的问题不清楚，您可以再次像我一样，，，，，

Answer 1

这段代码非常简单，可以在 sqlite3 表中插入值

 -(void)writeValueInSettings:(NSMutableArray *)arrayvalue

   {   


  if(sqlite3_open([databasePath UTF8String],&myDatabase)==SQLITE_OK)

     {
     database *objectDatabase=[[database alloc]init];

     NSString *stringvalue2=[objectDatabase countValue];

    [objectDatabase release];

     NSLog(@"opened");
     NSString *sql1;

sql1=[[NSString alloc] initWithFormat:@"insert into setting values('%i','%i','%i','%@','%i','%i','%@','%i','%i','%i','%i','%i','%i','%@');",intvalue1,
        [[arrayvalue objectAtIndex:0] intValue],[[arrayvalue objectAtIndex:1] intValue],[arrayvalue objectAtIndex:2],[[arrayvalue objectAtIndex:3] intValue],[[arrayvalue objectAtIndex:4]intValue ],[arrayvalue objectAtIndex:5],[[arrayvalue objectAtIndex:6]intValue],[[arrayvalue objectAtIndex:7]intValue ],[[arrayvalue objectAtIndex:8] intValue],[[arrayvalue objectAtIndex:9] intValue],[[arrayvalue objectAtIndex:10]intValue ],[[arrayvalue objectAtIndex:11]intValue],[arrayvalue objectAtIndex:12]];
    char *err1; 
    if (sqlite3_exec(myDatabase,[sql1 UTF8String],NULL,NULL,&err1)==SQLITE_OK)
    {
        NSLog(@"value inserted:");

         UIAlertView *alert=[[UIAlertView alloc]initWithTitle:@"Attention" message:@"You  inserted successfully" delegate:self cancelButtonTitle:nil otherButtonTitles:@"Ok", nil];
        [alert show];
       [alert release];
    }
    [sql1 release];
    sqlite3_close(myDatabase);
  }

  }

Answer 2

您需要连接到数据库

- (sqlite3 *)database {
    if (nil == db) {
        NSString *path = <path to your database>;
        int res = sqlite3_open([path UTF8String], &db);
        if (res != SQLITE_OK){
            // handle the error.
            db = nil;
            return nil;
        }
    }
    return db;
}

然后你可以用查询来调用它

    -(void)executeQuery:(NSString *)query{


        sqlite3_stmt *statement;

        if (sqlite3_prepare_v2([self database], [query UTF8String], -1, &statement, NULL) == SQLITE_OK) {

            sqlite3_step(statement);

        }else{
            // handle the error.
        }

        sqlite3_finalize(statement);
    }

-(void)dealloc {
    //close database connection
    sqlite3_close(db);
    db = nil;
    [super dealloc];
}

Answer 3

嗨，如果您在用户输入文本字段中获取用户输入

NSString *qry=[NSString stringwithformat:@"插入 abc(name) 值 (\"%@\")", userinput.text ];
const char *sql = [qry UTF8string];
sqlite3 *联系数据库；

const char *dbpath = [databasePath UTF8String]; // 将 NSString 转换为 UTF-8

if (sqlite3_open(dbpath, &contactDB) == SQLITE_OK)
{
if (sqlite3_exec(contactDB, sql_stmt, NULL, NULL, &errMsg) == SQLITE_OK)
 { // SQL 语句执行成功
 }
} 别的 {
    //打开数据库失败
}

Answer 4

-(NSArray *) executeSelect:(NSString *)query {
//Data search block****************************************

char *zErrMsg;
char **result;
int nrow, ncol;



sqlite3_get_table(
                  [self database],              /* An open database */

                  [query UTF8String],       /* SQL to be executed */
                  &result,       /* Result written to a char *[]  that this points to */
                  &nrow,             /* Number of result rows written here */
                  &ncol,          /* Number of result columns written here */
                  &zErrMsg          /* Error msg written here */
                  );


NSMutableArray *returnArray = [NSMutableArray arrayWithCapacity:3];



for (int i=0; i<nrow; i++){
    [returnArray addObject:[NSString stringWithUTF8String:result[ncol + i]]];

}

sqlite3_free_table(result);

return returnArray;

}