我正在使用 pybind11 为我无法更改其源的 C++ 库创建 python 绑定。它包含一个定义具有右值引用参数(例如T &&val
)的成员函数的类。我无法创建与具有右值引用参数的成员函数的绑定,但绑定到具有相同参数的非成员函数按预期工作。
一个简化的示例如下所示:
struct Foo {
// Cannot create a pybinding for this method.
void print_ref(int &&v) const {
std::cout << "Foo::print_ref(" << to_string(v) << ")" <<std::endl;
}
};
// Pybinding for standalone function works as expected.
void print_ref(int&& val) {
std::cout << "print_ref(" << to_string(val) << ")" << std::endl;
};
pybind11 代码如下所示:
PYBIND11_MODULE(refref, m) {
py::class_<Foo>(m, "Foo")
// Both of these attempts to create a pybinding FAILs with same error.
.def("print_ref", &Foo::print_ref)
.def("print_ref", (void (Foo::*) (int&&)) &Foo::print_ref);
// This pybinding of standalone function is SUCCESSful.
m.def("print_ref", &print_ref);
}
第一次绑定尝试的编译错误是:
pybind11/bin/../include/site/python3.4/pybind11/pybind11.h:79:80: error: rvalue reference to type 'int' cannot bind to lvalue of type 'int'
initialize([f](const Class *c, Arg... args) -> Return { return (c->*f)(args...); },
^~~~
pybind11/bin/../include/site/python3.4/pybind11/pybind11.h:1085:22: note: in instantiation of function template specialization 'pybind11::cpp_function::cpp_function<void, Foo, int &&,
pybind11::name, pybind11::is_method, pybind11::sibling>' requested here
cpp_function cf(method_adaptor<type>(std::forward<Func>(f)), name(name_), is_method(*this),
^
refref.cpp:31:3: note: in instantiation of function template specialization 'pybind11::class_<Foo>::def<void (Foo::*)(int &&) const>' requested here
.def("print_ref", &Foo::print_ref);
关于我可能做错了什么的任何想法?由于它适用于非成员函数,我倾向于怀疑 pybind11 问题,但我想我会先在这里检查。