我正在尝试创建一个 VBScript 来查找和替换位于两个字符串之间的某个字符串。这是脚本将在其上执行的文件的示例:
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N1 ( POSTED FILE NAME - WORKNC POST )
N2 ( INPUT FILE NAME - _6033_Cavity__01.TBA)
N3 (DATE/TIME: Thu Mar 15 06:36:08 2018)
N4 G0 G40 G80 G90 G98
N5 G17
N6 G57H901
N7 G173W0.0
N8 B0.000
N9 (Tapper 0.250000)
N10 T21
N11 M06
N12 S100
N13 M843
N14 G173 W0.0
N15 (- )
N16 ( Tapping )
N17 G0 G90 X-0.0001 Y8.8135
N18 G43 Z10.0632 H21
N19 G01 F500. X-0.0001 Y8.8135
N20 G01 Z9.7163 F500.
N21 G98 G84 X-0.0001 Y8.8135 Z6.0376 R7.6376 E10.
N22 G80 G01 F500.
N23 X-0.0001 Y8.8135 Z9.7163
N24 X-0.0001 Y8.8135 Z9.7163
N25
N26 M845
N27 G91 G28 Z0
N28 G90
N29 G57H901
N30 G173W0.0
N31 B0.000
N32 (Drill 0.005000)
N33 T19
N34 M06
N35 S5000
N36 M3
N37 G173 W0.0
N38 (- )
N39 ( Contour Chamfer )
N40 G0 G90 X-0.0001 Y8.8135
N41 G43 Z9.7163 H19
N42 Z7.6375
N43 G01 Z9.8376 F500.
N44 X-0.0001 Y8.8135 Z10.0632
N45
N46 M05
N47 G91 G28 Z0
N48 G90
N49 G57H901
N50 G173W0.0
N51 B0.000
N52 (Tapper 0.750000)
N53 T21
N54 M06
N55 S100
N56 M843
N57 G173 W0.0
N58 (- )
N59 ( Tapping )
N60 G0 G90 X-0.0001 Y8.8135
N61 G43 Z10.0632 H21
N62 G01 F500. X-0.0001 Y8.8135
N63 G01 Z9.7163 F500.
N64 G98 G84 X-0.0001 Y8.8135 Z6.0376 R7.6376 E10.
N65 G98 G84 X-0.0001 Y10.8135 Z6.0376 R7.6376 E10.
N66 G80 G01 F500.
N67 X-0.0001 Y8.8135 Z9.7163
N68 X-0.0001 Y8.8135 Z9.7163
N69
N70 M845
N71 G91 G28 Z0
N72 G90
N73 M30
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所以在这个特定的代码中有两个 Tapping 操作。我正在尝试制作一个看起来介于Tapper 0.250000
和之间的脚本M845
,并将 的所有实例替换E10.
为基于 中的数字的变量Tapper 0.250000
。
因此,例如,假设Tapper 0.250000
后面有一些 X 行M845
,这两者之间发生的E10.
's 需要替换为E0.250000
. 如果还有其他攻丝操作,例如在 Tapper 和 M845 之间Tapper 0.750000
的E10.
's 需要替换为E0.787
。
到目前为止,这是我的 VBScript:
strFileName = Wscript.Arguments(0)
strOutputFile = Wscript.Arguments(0)
Set fso = CreateObject("Scripting.FileSystemObject")
'Variable patterns to search for. There may be 9 of these total
strPattern25 = "(Tapper 0.250000)(.|\s)*(M845)"
strPattern375 = "(Tapper 0.375000)(.|\s)*(M845)"
strPattern5 = "(Tapper 0.500000)(.|\s)*(M845)"
strPattern75 = "(Tapper 0.750000)(.|\s)*(M845)"
strFindString = "E10." 'String to find and then replace each instance of between pattern
'Variables of the replace string
strReplaceString25 = "E0.05"
strReplaceString375 = "E0.0625"
strReplaceString5 = "E0.0769"
strReplaceString75 = "E0.787"
strTestString = fso.OpenTextFile(strFileName, 1).ReadAll 'open and read the file
'Replacing script. Currently replaces all text between the strPattern. Need to create another function in order to only replace the E10.
strNewText25 = fReplaceText(strPattern25, strTestString, strReplaceString25)
strNewText375 = fReplaceText(strPattern375, strTestString, strReplaceString375)
strNewText5 = fReplaceText(strPattern5, strTestString, strReplaceString5)
strNewText75 = fReplaceText(strPattern75, strTestString, strReplaceString75)
fso.OpenTextFile(strOutputFile, 2, True).WriteLine strNewText
MsgBox "Done!"
'Function
Function fReplaceText(sPattern, sStr, sReplStr)
Dim regEx, oMatch, colMatches, temp
Set regEx = New RegExp ' Create a regular expression.
regEx.Pattern = sPattern ' Set pattern
regEx.IgnoreCase = True ' Set case insensitivity.
regEx.Global = True ' Set global applicability
Set colMatches = regEx.Execute(sStr) ' Execute search
If colMatches.Count = 0 Then
temp = ""
Else
For Each oMatch In colMatches
temp = regEx.Replace(sStr, oMatch.SubMatches(0) & vbCrlf & sReplStr & vbCrlf & oMatch.SubMatches(2))
Next
End If
fReplaceText = temp
End Function