1

我在 reactjs 中构建了一个无限滚动，当用户点击页面底部时，数据是从同一个 API 加载的。现在，这里的问题是从多个不同的 API 获取数据以获取其他数据。那么，实现这一目标的正确方法是什么。请帮我解决这个问题。这是我的代码。

import React from "react";
import { Link } from 'react-router-dom';
import axios from 'axios';
const BUSY = {};

class InfiniteData extends React.Component{

constructor(props){
super(props);
this.state={
  olddata: [],
  newData: [],
  requestSent: false,
  scrollCounter:1
  }
  this.handleOnScroll = this.handleOnScroll.bind(this)
  this.buildData = this.buildData.bind(this)
}

componentDidMount(){
  window.addEventListener('scroll', this.handleOnScroll);
  this.doQuery(1).then(res=>
    this.setState({
     newData: this.state.newData.slice().concat(res),
    requestSent: false
  }))
}

componentWillUnmount() {
  window.removeEventListener('scroll', this.handleOnScroll);
}
queryActive = false;
doQuery(queryParam) {
  if(this.queryActive){
    return Promise.resolve(BUSY);
  }
  this.queryActive=true;
  switch(queryParam){
    case 1: return this.buildData(queryParam).then((res)=>res).catch(err=>{})
    break;
    case 2: return this.buildData(queryParam).then((res)=>res);
    break;
    case 3: return this.buildData(queryParam).then((res)=>res);
    break;
    case 4: return this.buildData(queryParam).then((res)=>res);
    break;
    default: return true;
  }

}

buildData(queryParam){
  //there is no paging in getting posts, won't it just get the same posts?
  return axios.get("https://jsonplaceholder.typicode.com/posts")
  .then( res=> {this.queryActive=false;return res.data;})
  .catch(err=>{
    this.queryActive=false;
    return Promise.reject(err);
  })
}


handleOnScroll(){
  var scrollCounter=0;
  var scrollTop = (document.documentElement && document.documentElement.scrollTop) || document.body.scrollTop;
  var scrollHeight = (document.documentElement && document.documentElement.scrollHeight) || document.body.scrollHeight;
  var clientHeight = document.documentElement.clientHeight || window.innerHeight;
  var scrolledToBottom = Math.ceil(scrollTop + clientHeight) >= scrollHeight;
  if (scrolledToBottom) {
    this.setState({
      scrollCounter: this.state.scrollCounter + Math.floor(scrolledToBottom)
    })
    if(this.state.scrollCounter<5){
      this.doQuery(this.state.scrollCounter).then(res=>
      (res===BUSY)
        ? false
        : this.setState({
            newData: this.state.newData.slice().concat(res)
          })
        )
        .catch(err=>this.setState({requestSent: false}))
        this.setState({requestSent: true});
    }else{
      return true
    }

  }
}

  render()
  {
    return (
    <div>
      <div className="data-container">
      <div  className="row ">
        {this.state.newData && this.state.newData.map((dat,i)=>
          <div key={i} className="col-lg-4">
              <div className="bordered">
                {dat.body}
              </div>
            </div>
        )}
          </div>
      </div>
    </div>
    );
  }
}

export default InfiniteData;
4

1 回答 1

2

您可以添加一个名为 BUSY 的常量，供 doQuery 用作它已经忙于发出请求时的返回值：

import React from "react";
import { Link } from 'react-router-dom';
import axios from 'axios';
const BUSY = {};

您可以对 doQuery 进行一些更改：

queryActive = false;
doQuery() {
  if(this.queryActive){
    return Promise.resolve(BUSY);
  }
  this.queryActive=true;
  //there is no paging in getting posts, won't it just get the same posts?
  return axios.get("https://jsonplaceholder.typicode.com/posts")
  .then( res=> {this.queryActive=false;return res.data;})
  .catch(err=>{
    //before you were only console.logging the error but that causes you
    //  to create a promise that doesn't reject but resolves with undefined
    //  when something goes wrong
    this.queryActive=false;
    console.warn(err);
    return Promise.reject(err);
  })
}

当您调用 doQuery 时，请确保如果结果为 BUSY，则忽略结果：

this.doQuery().then(res=>
  (res===BUSY)
    ? false
    : this.setState({
        newData: this.state.newData.slice().concat(res)
      })
)
.catch(err=>this.setState({requestSent: false}))
this.setState({requestSent: true});
于 2018-02-09T10:25:48.657 回答