python - 如何使用 exchangelib 获取非收件箱文件夹的邮件

Question

我想获取非收件箱文件夹的邮件 - 我该怎么做？

我可以像这样获取收件箱文件夹的电子邮件：

from exchangelib import DELEGATE, Account, Credentials, EWSDateTime

creds = Credentials(
    username='xxx.test.com\test',
    password='123456')
account = Account(
    primary_smtp_address='test@test.com',
    credentials=creds,
    autodiscover=True,
    access_type=DELEGATE)

# Print first 100 inbox messages in reverse order
for item in account.inbox.all().order_by('-datetime_received')[:100]:
    # print(item.subject, item.body, item.attachments)
    print(item.subject)

给予：

hahaha
heiheihei
pupupu
bibibib
........

当我得到我的文件夹时：

from exchangelib.folders import Messages

for f in account.folders[Messages]:
    print f

Messages (aaa)
Messages (bbb)
Messages (ccc)

如何ccc使用 Python 从文件夹中取出电子邮件？

Answer 1

查看最近版本中的文件夹导航选项exchangelib：https ://github.com/ecederstrand/exchangelib#folders

您可以像这样打印整个文件夹结构：

print(account.root.tree())

然后使用与以下相同的语法导航到特定文件夹pathlib：

some_other_folder = account.inbox / 'some_inbox_subfolder'
# Or:
some_other_folder = account.root / 'some' / 'other' / 'path'
for item in some_other_folder.all().order_by('-datetime_received')[:100]:
    print(item.subject)

Answer 2

您只能对收件箱子文件夹执行以下操作：

for subfolder in account.inbox.children:
    for emailz in subfolder.all().only('subject','attachments','datetime_sent').order_by('-datetime_received'):
        #do your thing

或所有根子文件夹：

for subfolder in account.root.children:
    for emailz in subfolder.all().only('subject','attachments','datetime_sent').order_by('-datetime_received'):
        #do your thing