spring-boot - 在 springboot 1.5.3 和 jaxrs 中格式化 java.time.Instant bean 属性

Question

我正在使用 Jaxrs，使用 springboot 1.5.x 创建 Rest 服务。我有一个具有 Instant 属性的 bean。当我打电话给我的服务而不是得到

{
 "startTime": {
        "epochSecond": 1517243670,
        "nano": 986000000
     }
 }

我想得到一个iso格式的日期，即{"startTime":"2018-01-29T17:51:05"}

public class MyController{
 @GET
 @Path("/")
 public MyBean test();
  return new MyBean(Instant.now());  
}

public class MyBean{
 private Instant startTime;
}

我添加了 java-8-time 依赖项

    <dependency>
        <groupId>com.fasterxml.jackson.datatype</groupId>
        <artifactId>jackson-datatype-jsr310</artifactId>
        <version>2.9.3</version>
    </dependency>
    <dependency>
        <groupId>com.fasterxml.jackson.datatype</groupId>
        <artifactId>jackson-datatype-jdk8</artifactId>
        <version>2.8.0</version>
    </dependency>
    <dependency>
        <groupId>com.fasterxml.jackson.module</groupId>
        <artifactId>jackson-module-parameter-names</artifactId>
        <version>2.8.7</version>
    </dependency>

并尝试了几种方法，但都没有奏效。

1. @JsonFormat属性上的注释

   @JsonFormat(shape=JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss") private Instant startTime;

2. ObjectMapper在应用程序配置中 @Bean @Primary public ObjectMapper objectMapper(Jackson2ObjectMapperBuilder builder) { ObjectMapper objectMapper = builder.build(); objectMapper.registerModule(); objectMapper.configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false); return objectMapper; }

3. 使用@Provider

   public class ObjectMapperContextResolver implements 
   ContextResolver<ObjectMapper>{
   private final ObjectMapper MAPPER;
   
   public ObjectMapperContextResolver() {
       MAPPER = new ObjectMapper();
       SimpleModule module = new SimpleModule();
       MAPPER.registerModule(new JSR310Module());
       MAPPER.registerModule(new JavaTimeModule());
       module.addSerializer(Instant.class, new DateSerializer());
       module.addDeserializer(Instant.class, new DateDeserializer());
       MAPPER.registerModule(module);
   
       MAPPER.configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false);
   }
   @Override
   public ObjectMapper getContext(Class<?> type) {
       return MAPPER;
   }
   

4. 使用自定义序列化/反序列化

   @JsonDeserialize(using=DateDeserializer.class)
   @JsonSerialize(using=DateSerializer.class)
   private Instant startTime;
   
   public class DateDeserializer extends JsonDeserializer<Instant>{
    @Override
    public Instant deserialize(JsonParser jp, DeserializationContext arg1)
       throws IOException, JsonProcessingException {
    return Instant.parse(jp.readValueAs(String.class));
    }
   }
   
   public class DateSerializer extends JsonSerializer<Instant> {
    @Override
    public void serialize(Instant value, JsonGenerator gen, 
    SerializerProvider sp) throws IOException {...}
   

我显然在这里遗漏了一些东西。