使用的技术：
- Firebase 云消息传递
- 斯威夫特 3.2
- Xcode 9.2
为了给你一个背景，这里是我通过 FCM 在 api 服务器上发送的数据
{
"priority": "high",
"content_available": true,
"alert": true,
"sound": true,
"registration_ids": [
"<SOME_ID_HERE>",
"<SOME_ID_HERE>"
],
"notification": {
"title": "SOME TITLE",
"body": "SOME BODY"
},
"data": {
"some_key": "some_value",
"some_key2": "some_value2"
}
}
应用程序正确接收了此信息，并且我以正确的方式正确使用了这些方法
application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable: Any], fetchCompletionHandler completionHandler: @escaping (UIBackgroundFetchResult) -> Void)
messaging(_ messaging: Messaging, didReceive remoteMessage: MessagingRemoteMessage)
messaging(_ messaging: Messaging, didRefreshRegistrationToken fcmToken: String)
userNotificationCenter(_ center: UNUserNotificationCenter, didReceive response: UNNotificationResponse, withCompletionHandler completionHandler: @escaping () -> Void)
userNotificationCenter(_ center: UNUserNotificationCenter, willPresent notification: UNNotification, withCompletionHandler completionHandler: @escaping (UNNotificationPresentationOptions) -> Void)
当应用程序处于后台/使用此示例代码终止时，有没有办法以某种方式忽略推送通知？
func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable: Any], fetchCompletionHandler completionHandler: @escaping (UIBackgroundFetchResult) -> Void) {
switch application.applicationState {
case .inactive, .background:
// Tell Firebase that we recieved the Push Notification
self.messaging.appDidReceiveMessage(userInfo)
// `PushNotification` is a model that parses the `userInfo` dictionary
guard let pushNotification: PushNotification = PushNotification(userInfo) else {
return // end code execution cause push cannot be parsed
}
if pushNotification.isSomeKindOfThing {
// ignore
} else {
// do nothing so it will show
}
case .active:
// handle when application is active
}
}
我的目标是，当我收到推送通知时，我可以根据"data"密钥中的内容忽略它。