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我正在尝试通过 HttpClient 获取数据。数据大小不一,可能从几字节到兆字节不等。我注意到很多时候我的应用程序甚至在它从 GetAsync 返回之前就已经存在。我怎样才能等到 GetAsync 完成它的调用?从主应用程序: -

        backup.DoSaveAsync();
        Console.ForegroundColor = ConsoleColor.Yellow;
        Console.BackgroundColor = ConsoleColor.Red;
        // My app exist by printing this msg, wihout getting any data. 
        // someitmes it gets data and other times it gets notinng.
        // I used sleep to wait to get the call completed. 
        Console.WriteLine("\nBackup has done successfully in SQL database")

        public async void DoSaveAsync()
        {
            using (var client = GetHttpClient(BaseAddress, path, ApiKey))
            {
                Stream snapshot = await  GetData(client, path);

                if (snapshot != Stream.Null)
                {
                    snapshot.Position = 0;
                    SaveSnapshot(snapshot);
                }
            }
        }

   private async Task<Stream> GetData(HttpClient client, string path)
    {
        HttpResponseMessage response = null;
        try
        {
            response = await client.GetAsync(path);
            System.Threading.Thread.Sleep(5000);
            if (response.IsSuccessStatusCode == false)
            {
                Console.WriteLine($"Failed to get snapshot");
                return Stream.Null;
            }
            return await response.Content.ReadAsStreamAsync();
        }
        catch (Exception ex)
        {
            Console.WriteLine(ex.Message);
            return Stream.Null;
        }
    }

评论和回答后的代码更新:

     // in my main app, I have this code. 
     // How can I get the completed task or any error return by the task here.
    backup.DoBackupAsync().Wait();

    public async Task<Stream> DoSaveAsync()
    {
        using (var client = GetHttpClient(BaseAddress, SnapshotPath, ApiKey))
        {
            try
            {
                Stream snapshot = await GetSnapshot(client, SnapshotPath);

                if (snapshot != Stream.Null)
                {
                    snapshot.Position = 0;
                    SaveSnapshot(snapshot);
                }
                return snapshot;
            }
            catch (Exception ex)
            {
                Console.WriteLine(ex.Message);
                return null;
            }

        }
    }
4

1 回答 1

2

由于该方法是异步的,因此该backup.DoSaveAsync()行仅启动一个任务但不等待结果,因此您可以Console.ReadLine在任务完成之前调用(并可能退出您的程序)。您应该返回Task而不是void- 拥有 void 异步方法通常是不好的设计,并且您必须backup.DoSaveAsync()通过 await (如果您从异步方法调用)或通过.Wait().

此外,如果出现错误GetData,您不会返回任何错误DoSaveAsync- 您可能想要处理此问题,在当前代码中,您将打印“无法获取快照”,然后“备份已在 SQL 数据库中成功完成” . 考虑不使用 Console.ReadLineGetData并返回一个DoSaveAsync指示成功的任务

无需在thread.sleep这里放置 - 你已经在等待结果了。

于 2018-01-07T21:17:37.637 回答