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我目前正在处理我的小型数据库项目,但我已经遇到了问题。我有两个表,生成的脚本发布在下面,现在我正在尝试编写一个程序,该程序将首先将记录添加到较小的记录中,然后使用第一个记录中的 ID 添加到第二个记录。但是我收到一个错误:“列名或提供的值的数量与表定义不匹配。” 在尝试将默认值添加到表 Klienci 的行中。我不知道发生了什么,因为没有列或参数,所以应该没有问题,至少像这个一样。

第一张表:

SET ANSI_NULLS ON
GO

SET QUOTED_IDENTIFIER ON
GO

CREATE TABLE [dbo].[KlienciIndywidualni](
    [IDKlientaIndywidualnego] [int] IDENTITY(1,1) NOT NULL,
    [IDKlienta] [int] NOT NULL,
    [Imie] [nvarchar](50) NOT NULL,
    [Nazwisko] [nvarchar](50) NOT NULL,
    [NumerLegitymacji] [int] NULL,
    [Adres] [nvarchar](50) NOT NULL,
    [Miasto] [nvarchar](50) NOT NULL,
    [KodPocztowy] [nvarchar](50) NOT NULL,
    [Kraj] [nvarchar](50) NOT NULL,
    [Telefon] [int] NOT NULL,
    [Email] [nvarchar](50) NOT NULL,
 CONSTRAINT [PK_KlienciIndywidualni] PRIMARY KEY CLUSTERED 
(
    [IDKlientaIndywidualnego] ASC
)WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = OFF,     ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY]
) ON [PRIMARY]

GO

ALTER TABLE [dbo].[KlienciIndywidualni]  WITH CHECK ADD  CONSTRAINT [FK_KlienciIndywidualni_Klienci] FOREIGN KEY([IDKlienta])
REFERENCES [dbo].[Klienci] ([IDKlienta])
GO

ALTER TABLE [dbo].[KlienciIndywidualni] CHECK CONSTRAINT [FK_KlienciIndywidualni_Klienci]
GO

ALTER TABLE [dbo].[KlienciIndywidualni]  WITH CHECK ADD  CONSTRAINT [CK_KlienciIndywidualni] CHECK  ((len([Telefon])>=(9)))
GO

ALTER TABLE [dbo].[KlienciIndywidualni] CHECK CONSTRAINT [CK_KlienciIndywidualni]
GO

ALTER TABLE [dbo].[KlienciIndywidualni]  WITH CHECK ADD  CONSTRAINT [CK_KlienciIndywidualni_mail] CHECK  (([Email] like '%@%.[a-z][a-z][a-z]'))
GO

ALTER TABLE [dbo].[KlienciIndywidualni] CHECK CONSTRAINT [CK_KlienciIndywidualni_mail]
GO

第二个:

SET ANSI_NULLS ON
GO

SET QUOTED_IDENTIFIER ON
GO

CREATE TABLE [dbo].[Klienci](
    [IDKlienta] [int] IDENTITY(1,1) NOT NULL,
CONSTRAINT [PK_Klienci] PRIMARY KEY CLUSTERED 
(
    [IDKlienta] ASC
)WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = OFF,   ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY]
) ON [PRIMARY]

GO

程序:

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

CREATE PROCEDURE dodaj_klienta_indywidualnego 
-- parametry
@Imie nvarchar(50),
@Nazwisko nvarchar(50),
@Adres nvarchar(50),
@KodPocztowy nvarchar(50),
@Miasto nvarchar(50) ,
@Kraj nvarchar(50),
@Telefon int,
@Email nvarchar(50),
@NumerLegitymacji nvarchar(50) = null

AS
BEGIN

SET NOCOUNT ON;
declare @IDKlienta as int;

begin try
    begin tran
    --dodaj klienta
    INSERT INTO Klienci
    DEFAULT VALUES
    set @IDKlienta = @@IDENTITY;

    --dodaj klienta indywidualnego
    INSERT INTO KlienciIndywidualni
    VALUES(@IDKlienta, @Imie, @Nazwisko, @Adres, @Miasto, 
    @KodPocztowy, @Kraj, @Telefon, @Email);
    COMMIT TRAN
end try
begin catch
    declare @error as varchar(127)
    set @error = (Select ERROR_MESSAGE())
    RAISERROR('Nie mozna dodac osoby-klienta, blad danych. %s', 16, 1, @error);
    ROLLBACK TRAN
end catch
END
GO
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1 回答 1

2

您的第二次插入需要十个参数,您只提供了 9 个,如果您将跳过该NumerLegitymacji字段,那么您应该按其名称指定每列,因为现在插入等待最后一个 NOT NULL 列。

    --dodaj klienta indywidualnego
    INSERT INTO KlienciIndywidualni (
    IDKlienta,
    Imie,
    Nazwisko,
    Adres,
    Miasto,
    KodPocztowy,
    Kraj,
    Telefon,
    Email
)
    VALUES(@IDKlienta, @Imie, @Nazwisko, @Adres, @Miasto, 
    @KodPocztowy, @Kraj, @Telefon, @Email);
    COMMIT TRAN
于 2013-01-18T22:56:27.827 回答