17

我是 django (1.2.4) 的新手。我用通用视图创建了一些杂物。但是,当使用 django 的消息传递框架创建学生时,如何显示“学生已成功添加”之类的内容?

4

4 回答 4

45

Django 1.6+开始,使用任何基于类的通用视图,您都可以依赖successMessageMixin。就像将 mixin 添加到您的类定义并将success_message属性设置为您想要的任何内容一样简单。

正如 Olivier Verdier 所说,请记住在主模板中显示消息!

文档中的一个简单示例:

from django.contrib.messages.views import SuccessMessageMixin
from django.views.generic.edit import CreateView
from myapp.models import Author

class AuthorCreate(SuccessMessageMixin, CreateView):
    model = Author
    success_url = '/success/'
    success_message = "%(name)s was created successfully"

一个更复杂的例子:

from django.contrib.messages.views import SuccessMessageMixin
from django.views.generic.edit import CreateView
from myapp.models import ComplicatedModel

class ComplicatedCreate(SuccessMessageMixin, CreateView):
    model = ComplicatedModel
    success_url = '/success/'
    success_message = "%(calculated_field)s was created successfully"

    def get_success_message(self, cleaned_data):
        #  cleaned_data is the cleaned data from the form which is used for string formatting
        return self.success_message % dict(cleaned_data,
                                           calculated_field=self.object.calculated_field)
于 2014-02-06T10:10:35.953 回答
4

据我所知,使用传统的通用视图并没有一种直接的方法。我一直觉得通用视图的文档非常缺乏,因此从未使用过它们。

理论上,您可以通过假设重定向意味着成功提交来使用装饰器。

所以你可以写这样的东西(这些代码都没有经过测试):

urls.py

try:
    from functools import wraps
except ImportError:
    from django.utils.functional import wraps
from django.http import HttpRedirectResponse
from django.contrib import messages
from django.views.generic import * 

def add_message(success_message=None):
    def decorator(func):
        def inner(request, *args, **kwargs):
            resp = func(request, *args, **kwargs)
            if isinstance(resp, HttpRedirectResponse):
                messages.success(request, message)
            return resp
        return wraps(func)(inner)
    return decorator



student_info_edit = {
  'template_name': 'myapp/student/form.html',
  'template_object_name': 'student',
  'form_class':  studentForm,
}

student_info_new = {
  'template_name': 'myapp/student/form.html',
  'form_class':  studentForm,
  'post_save_redirect': '/myapp/students/',
}

urlpatterns += patterns('',
  url(r'^students/$', list_detail.object_list, { 'queryset': Student.objects.all() }, name="students"),
  url(r'^students/(?P<object_id>\d+)/$', add_message("Student record updated successfully")(create_update.update_object), student_info_edit, name="student_detail"),
  url(r'^students/new$', add_message("The student was added successfully.")(create_update.create_object), student_info_new, name="student_new"),
)

说了这么多,Django 1.3 引入了基于类的通用视图,所以如果你对迁移到 Django 1.3 感兴趣,你应该研究一下。他们可能允许更多的定制,不确定。

从长远来看,我很少看到使用通用视图的好处形式,这对于添加/更新之类的东西来说是双倍的。

于 2011-01-26T09:22:43.430 回答
2

您要求的功能已经在 Django 通用视图中实现:

https://github.com/django/django/blob/1.2.X/django/views/generic/create_update.py#L115

您将通过在主模板中显示消息来查看消息。

于 2011-04-03T07:59:51.990 回答
0

实际上,我认为文档很好地解释了基于通用/功能的视图: https ://docs.djangoproject.com/en/2.0/ref/contrib/messages/

它基本上使用 if 语句将上下文传递给您的模板以显示或不显示该上下文。

看法:

from django.contrib import messages
def home_page(request):
    if request.method == 'POST':
        messages.success(request, 'Student added successfully')
        context = {}
        return render(request, 'homepage/index.html', context)
    else:
        form =yourForm()
        return render(request, 'homepage/index.html', form)

然后它将使用以下内容显示在您的模板中。记住要迭代'...因为否则消息存储将不会为下一个请求被清除':

{% if messages %}
<ul class="messages">
    {% for message in messages %}
    <li{% if message.tags %} class="{{ message.tags }}"{% endif %}>{{ message }}</li>
    {% endfor %}
</ul>
{% endif %}

当它再次呈现页面时,只需向您的表单添加一个锚标记并包含在您的表单操作中,即

action="{% url 'home_page:index' %}#subscribe"

如果您使用引导添加类alert-success

于 2018-05-30T10:51:34.007 回答