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我正在解决欧拉项目3：

Description: The prime factors of 13195 are 5, 7, 13 and 29.
             What is the largest prime factor of the number 600851475143 ?

这是我生成答案的代码。但是我需要一个整数类型来保存600851475143。当我在 Mac 上的 GCC 上编译它时，我得到：

integer constant is too large for ‘long’ type".

我预计long long可以轻松持有这个数字。我也试过让它不签名。为什么我的代码没有这么小的数字，我该怎么做才能让它工作？

#include <iostream>
#include <vector>

using namespace std;

static bool IsPrimeFactor(int numToTest,int testNum,vector<int> factors)
{
    if(numToTest%testNum==0) // is it a factor?
    {
        // see if it is a prime factor
        for(unsigned int i=0; i < factors.size(); i++)
        {
            if(testNum%factors[i]==0)  // see if this factor
            {                          //is divisble by one we have already

                return false;
            }
        }

        return true;
    }
    return false;
}

int main() {
    unsigned long long numToTest=600851475143;
    unsigned int testNum=2;  // 0 and 1 are assumed
    vector<int> factors;   

    while(testNum<numToTest)   // don't go higher than the max num
    {
        if(IsPrimeFactor(numToTest,testNum,factors)) // is it a factor?
        {
            factors.push_back(testNum); // got through prime factors 
        }                                   // and none divided it

        testNum++;
    }

    for(unsigned int i=0; i < factors.size(); i++)
    {
        cout << "factor " <<factors[i] << endl;
    }

    cout<<"Highest factor: " << factors[factors.size()-1]<<endl;

    return 0;
}
4

2 回答 2

6

检查这个问题。你必须像这样指定你的文字：

600851475143LL
于 2011-01-25T11:33:52.357 回答
1

正如@Space_C0wb0y 所说，您需要为文字指定后缀。

此外，您的IsPrimeFactor函数会出现问题 - 参数是整数，但正如您已经发现的那样，整数甚至长整数都不足以存储您将重复传递的数字。 .

于 2011-01-25T11:37:44.473 回答