mysql - SQL 用于根据评分获取顶级用户并使用结果获取附加数据

Question

我正在尝试想出一个可以获取每个

• 国名，
• 代码，
• 游戏数量，
• TOP球员的名字和
• 他的身份证
• 基于游戏表中的 SUM（评级）。

我无法根据评分获得顶级球员的名字。

SQLFiddle 演示

Answer 1

SELECT  x.Country AS CountryName,
        x.Code,
        a.totalCount as NumberOfGames,
        y.Name AS PlayersName,
        y.ID AS PlayersID,
        a.totalRating
FROM    (
            SELECT  player_ID, Country, COUNT(*) totalCount, SUM(Rating) totalRating
            FROM    Games
            GROUP BY player_ID, Country
        ) a 
        INNER JOIN
        (
            SELECT Country, Max(totaLRating) maxRating
            FROM
            (
                SELECT  player_ID, Country, SUM(Rating) totalRating
                FROM    Games
                GROUP BY player_ID, Country
            ) s
            GROUP BY Country
        ) b ON a.Country = b.Country AND
                a.totalRating = b.maxRating
        INNER JOIN Country x
            ON a.Country = x.ID
        INNER JOIN Players y
            ON a.player_ID = y.ID

• SQLFiddle 演示

Answer 2

select top 1 * from games inner join players on games.player_id=players.id inner join country on games.country=country.id order by rating desc

Answer 3

试试这个查询

select 
    c.id as country_id,
    c.name as Country,
    c.code as CCode,
    g.T_Games,
    p.id as Player_id,
    p.name as Player
from country as c
left join (select country , count(country) as T_Games from games group by country) as g on g.country = c.id
left join (select id , country , player_id , max(rating) from games group by country) as gl on gl.country = c.id
left join (select id , name from player) as p on p.id = gl.player_id

这是关于 sql fiddle 的演示

http://sqlfiddle.com/#!2/f74a7/1