7

我正在尝试构建一个结合ggplot2和的情节plotly。两条垂直线出现在纯 ggplot2 上，但一旦我调用plotly::ggplotly它，它们就会消失。如何使数据也出现在ggplotly版本上？如果你有一个只使用的解决方案plot_ly，那也很好。

数据：

df <- structure(list(date = structure(c(17226, 17257, 17287, 17318, 
17348, 17379, 17410, 17440, 17471, 17501, 17226, 17257, 17287, 
17318, 17348, 17379, 17410, 17440, 17471, 17501, 17226, 17257, 
17287, 17318, 17348, 17379, 17410, 17440, 17471, 17501), class = "Date"), 
    n = c(253L, 217L, 257L, 166L, 121L, 56L, 68L, 62L, 142L, 
    20L, 174L, 228L, 180L, 158L, 80L, 39L, 47L, 54L, 107L, 12L, 
    93L, 74L, 47L, 49L, 55L, 16L, 52L, 53L, 32L, 3L), act = c("a", 
    "a", "a", "a", "a", "a", "a", "a", "a", "a", "b", "b", "b", 
    "b", "b", "b", "b", "b", "b", "b", "c", "c", "c", "c", "c", 
    "c", "c", "c", "c", "c")), class = "data.frame", row.names = c(NA, 
-30L), .Names = c("date", "n", "act"))

facts_timeline <- structure(list(Date = structure(c(17507, 17293), class = "Date"), 
    ShortDescription = c("Marketing Campaign", "Relevant Fact 1"
    )), row.names = c(NA, -2L), class = c("tbl_df", "tbl", "data.frame"
), spec = structure(list(cols = structure(list(Date = structure(list(
    format = ""), .Names = "format", class = c("collector_date", 
"collector")), Tenant = structure(list(), class = c("collector_character", 
"collector")), ShortDescription = structure(list(), class = c("collector_character", 
"collector")), LongDescription = structure(list(), class = c("collector_character", 
"collector"))), .Names = c("Date", "Tenant", "ShortDescription", 
"LongDescription")), default = structure(list(), class = c("collector_guess", 
"collector"))), .Names = c("cols", "default"), class = "col_spec"), .Names = c("Date", 
"ShortDescription"))

制作情节的代码：

p <- df %>% 
  ggplot(aes(date, n, group = act, color = act)) + 
  geom_line() + 
  geom_vline(data = facts_timeline, aes(xintercept = Date))

在这里你可以看到两条垂直线：

p

但不是在这里：

ggplotly(p)
4

3 回答 3

17

只需将 设置xintercept为数字，一切都会奏效。

p <- df %>% 
  ggplot(aes(date, n, group = act, color = act)) + 
  geom_line() + 
  geom_vline(data = facts_timeline, aes(xintercept = as.numeric(Date)))

p

ggplotly(p)

在此处输入图像描述

于 2018-10-10T08:07:27.310 回答
2

不能直接在 plotly 中绘制垂直线，但这是我的解决方法：

vline_list <- list()
for(i in 1:nrow(facts_timeline)){ 
  vline_list[[i]] <- 
    list(type      = "line",
         fillcolor = line_color, 
         line      = list("black"),
         opacity   = 0.3,
         x0        = facts_timeline$Date[i],
         x1        = facts_timeline$Date[i],
         xref      = "x",
         y0        = 0, 
         y1        = max(df$n),
         yref      = "y")
}

plot_ly(x = ~df$date, y = ~df$n,color = df$act, mode = 'lines') %>% 
  layout(shapes  = vline_list)

使用 for 循环，我们遍历所有行facts_timeline并创建一个新行。这条线没有 ggplot 中的无限长。在我的示例中，该线是 y 轴的最大值。您可以根据自己的需要更改此设置。

于 2017-12-11T14:14:49.230 回答
1 
plot_ly(df, 
        x = ~ date, 
        y = ~ n, 
        color = ~act, 
        text = ~act,
        mode = "lines", 
        type = "scatter",
        hoverinfo = "x+y+text") %>% 
    layout(hovermode = "closest",
        xaxis=list(range=c("2017-03-01", "2018-01-01"))) %>%
    add_lines(x=rep(facts_timeline[["Date"]][[1]], 2), 
        y=c(0, 300),
        name=facts_timeline[["ShortDescription"]][[1]],
        inherit=FALSE, 
        hoverinfo = "name",
        line = list(color="#000000")) %>% 
    add_lines(x=rep(facts_timeline[["Date"]][[2]], 2), 
        y=c(0, 300), 
        name=facts_timeline[["ShortDescription"]][[1]],
        inherit=FALSE, 
        hoverinfo = "name",
        line = list(color="#000000"))
于 2017-12-11T14:22:07.277 回答