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I make a list of ggplots stored in an object called g.a, Here's the code to reproduce the plots (data is provided at the bottom).

Worth to note that I am probably missing something simple and over-complicated the problem.

RCfitter <- function(w,h,a,b){(a * ((w + h)^b))}

fillfactor <- lapply(seq_len(length(dat.a)), function(i) {
              as.factor((gsub("-.*","",dat.a[[i]]$Date)))}) #I tried as.integer as well

set.seed(92)
lin.a <- lapply(seq_len(length(dat.a)), function(i) {
                          data.frame(x = runif(100, -dB.coef.a[3,i],
                          max(dat.a[[i]]$WL)+diff(0.2*range(dat.a[[i]]$Q))))})

library(ggplot2)

g.a <- lapply(seq_len(length(dat.a)), function(i) {
ggplot() + 
geom_point(data=dat.a[[i]], aes(x=WL,y=Q, tltip = Date,
fill =fillfactor[[i]]),
colour = NA, pch=21) + 

scale_fill_manual(breaks = mybreaks, values = myfills)+

geom_line(data = lin.a[[i]], 
          aes(x=x,y= RCfitter(x,dB.coef.a[3,i],dB.coef.a[1,i],dB.coef.a[2,i])),colour="red")+

xlab("WL") +
ylab("Q") +
ggtitle(paste("pLot ",i)) +
ylim(c(0,(max(dat.a[[i]]$Q)+diff(0.2*range(dat.a[[i]]$Q))))) +
xlim(c(0,(max(dat.a[[i]]$WL)+diff(0.2*range(dat.a[[i]]$WL))))) +
theme(legend.position="none")
                              })

If I ignore the scale_fill I can plot them and I will get the "colorful" plot. But with that I get this warning:

g.a[[2]]

##  Warning messages:
##  1: Removed 6 rows containing missing values (geom_point). 
##  2: Removed 64 rows containing missing values (geom_path).

Which means geom_point does not plot anything.

I used scale_fill_discrete, scale_fill_continuous, etc. and they give me errors like discrete value to continuous scale or vice versa or.

What I really want is to make a gradient color for years, let's say from blue to red, so I can distinguish between the years while seeing if there's a chunk of similar years (e.g. 60s) around the same spot.

P.S. At the end, I am using ggplotly() (e.g. ggplotly(g.a[[2]],tooltip = c("x","y","tltip")). So, if that would change the behavior of scale_fill (which is, for example, some of the colors that I have specified are invalid for plotly) , please have that in mind.

Sample Data:

dat.a

 dat.a <- list(structure(list(Date = c("1974-02-14", "1974-02-16", "1974-02-28",
     "1974-02-28", "1974-02-28", "1974-02-28"), WL = c(0.24, 0.135, 
     0.395, 0.26, 0.22, 0.31), Q = c(0.237, 0.04, 0.9, 0.36, 0.52,           
     0.56), Velocity = c(0.3, 0.103, 0.367, 0.209, 0.34, 0.276), Area = c(0.79, 
     0.388, 2.452, 1.722, 1.529, 2.029), Flag = c(NA_character_, NA_character_, 
     NA_character_, NA_character_, NA_character_, NA_character_), 
         Shift = c("/", "/", "/", "/", "/", "/"), date = structure(c(130032000,  
         130204800, 131241600, 131241600, 131241600, 131241600), class = c("POSIXct",  
         "POSIXt"), tzone = "UTC")), .Names = c("Date", "WL", "Q",  
     "Velocity", "Area", "Flag", "Shift", "date"), row.names = c(NA, 
     -6L), class = c("tbl_df", "tbl", "data.frame")), structure(list(          
         Date = c("1965-01-29", "1965-01-29", "1965-04-25", "1966-11-29",   
         "1967-01-24", "1967-11-12"), WL = c(0.439, 0.439, 0.482,     
         0.463, 0.427, 0.475), Q = c(0.252, 0.269, 0.403, 0.314, 0.199,
         0.4), Velocity = c(0.23, 0.232, 0.316, 0.279, 0.249, 0.36      
         ), Area = c(1.096, 1.159, 1.275, 1.125, 0.799, 1.111), Flag = c(NA_character_,  
         NA_character_, NA_character_, NA_character_, NA_character_,                   
         NA_character_), Shift = c("/", "/", "/", "/", "/", "/"),                      
         date = structure(c(-155347200, -155347200, -147916800, -97545600,    
         -92707200, -67478400), class = c("POSIXct", "POSIXt"), tzone = "UTC")), 
        .Names = c("Date","WL", "Q", "Velocity", "Area", "Flag", "Shift", "date"), 
        row.names = c(NA,-6L), class = c("tbl_df", "tbl", "data.frame")))

dB.coef.a

 dB.coef.a <- structure(c(-77.6915945552795, 0.594614568300253, 60.9718752625543, 
     7.96297849987566, 2.69599957356069, -0.183937755444007), .Dim = c(3L,        
     2L), .Dimnames = list(c("a", "b", "h"), NULL))

mybreaks

 mybreaks <- c(1955, 1956, 1959, 1960, 1961, 1962, 1963, 1964, 1965, 1966, 
     1967, 1968, 1969, 1970, 1971, 1972, 1973, 1974, 1975, 1976, 1977,     
     1978, 1979, 1980, 1981, 1982, 1983, 1984, 1985, 1986, 1987, 1988,     
     1989, 1990, 1991, 1992, 1993, 1994, 1995, 1996, 1997, 1998, 1999,     
     2000, 2001, 2002, 2003, 2004, 2005, 2006, 2007, 2008, 2009, 2010,     
     2011, 2012, 2013, 2014, 2015, 2016, 2017)

myfills

 myfills <- c("005ABF", "0358BC", "0757B9", "0A56B6", "0E54B3", "1153B0",  
     "1552AD", "1851AA", "1C4FA7", "1F4EA4", "234DA2", "264B9F", "2A4A9C", 
     "2D4999", "314896", "344693", "384590", "3B448D", "3F428A", "424187", 
     "464085", "493F82", "4D3D7F", "503C7C", "543B79", "573976", "5B3873", 
     "5E3770", "62366D", "65346A", "693368", "6D3265", "703062", "742F5F", 
     "772E5C", "7B2D59", "7E2B56", "822A53", "852950", "89274D", "8C264B", 
     "902548", "932445", "972242", "9A213F", "9E203C", "A11E39", "A51D36", 
     "A81C33", "AC1B30", "AF192E", "B3182B", "B61728", "BA1525", "BD1422", 
     "C1131F", "C4121C", "C81019", "CB0F16", "CF0E13", "D30D11")
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1 回答 1

1

一个建议，如果我正确理解了您的问题：

1.我有一条带有颜色 ( myfills) 的错误消息：

grDevices::col2rgb 中的错误（颜色，真）

#不见了 ：

mycolors <- paste0("#", myfills) # correct colors
names(mycolors ) <- mybreaks # name your colors
mycolors[names(mycolors) == "1965"] <- "#D30D11" # swapped color to red to check its ok


2.如果你真的不想要pch = 21for 的“颜色” geom_point，更好地使用pch = 16，那么忘记fill美学并color改用：

g.a <- lapply(seq_len(length(dat.a)), function(i) {
    ggplot(data = dat.a[[i]], aes(x = WL, y = Q, color = fillfactor[[i]])) + 
    geom_point(pch = 16) + 
    scale_color_manual(values = mycolors) +
    geom_line(data = lin.a[[i]], aes(x = x, y = RCfitter(x, dB.coef.a[3,i], dB.coef.a[1,i], dB.coef.a[2,i])), colour = "red") +
    ggtitle(paste("pLot ",i)) +
    ylim(c(0,(max(dat.a[[i]]$Q) + diff(0.2*range(dat.a[[i]]$Q))))) +
    xlim(c(0,(max(dat.a[[i]]$WL) + diff(0.2*range(dat.a[[i]]$WL))))) +
    theme(legend.position="none")
 }
)
g.a[[2]]

在此处输入图像描述

3.关于的警告信息geom_path是由于您的xlim().

于 2017-12-07T17:08:30.483 回答