:-)
我有两个数据集,我从中派生直方图数据。这些都保存在两个单独的数组中。当前的源代码可以在下面找到,以及当前的绘图。
# DEMO file for the awesome stackoverflow community
require(plotrix)
# clear the global environment ----
rm(list=ls())
# Assign demo data ----
data_T <- c(rep(1,5),rep(2,10),rep(3,8),rep(4,2),rep(5,7),rep(6,2),rep(7,13),rep(9,7))
data_P <- c(rep(1,1),rep(2,4),rep(3,1),rep(4,7),rep(5,12),rep(6,10),rep(7,9),rep(10,2))
# Setting the limits of the result data ----
uxlimit <- 10
lxlimit <- 0
classes <- (uxlimit-lxlimit)
xtics <- seq(lxlimit,uxlimit)
uylimit <- 20
lylimit <- 0
yrange <- seq(lylimit,uylimit, by = 5)
# filter out of necessary ----
data_T [ data_T > uxlimit ] <- NaN
data_T [ data_T < lxlimit ] <- NaN
data_T <- na.omit(data_T)
# Setting the x-label and y-label according to the requested spectrum ----
xlabel <- "x-value / x-unit"
ylabel <- "y-value / y-unit"
# generate histogram data ----
data_T_hist <- hist(data_T,
breaks = seq(lxlimit,uxlimit,l = classes+1),
plot = F)
data_P_hist <- hist(data_P,
breaks = seq(lxlimit,uxlimit,l = classes+1),
plot = F)
# Plot data_T_hist ----
plot(data_T_hist$breaks,
c(data_T_hist$counts,0),
xlab=xlabel,
ylab=ylabel,
ylim = c(lylimit,uylimit),
xlim = c(lxlimit,uxlimit),
main="Histogram data",
axes=F,
type="s",
col="red",
lwd=4,
panel.first = grid(nx=NULL, ny=NULL))
# Plot data_P_hist ----
lines(data_P_hist$breaks,
c(data_P_hist$counts,0),
xlab=xlabel,
ylab=ylabel,
ylim = c(lylimit,uylimit),
xlim = c(lxlimit, uxlimit),
type="s",
col="blue",
lwd=4,
lty=2)
# Frame all plots with a solid border ----
box(which = "plot", lty = "solid")
# Add legend to the top right of all plots ----
legend("topright",
c("data_T_hist", "data_P_hist"),
col=c("red","blue"),
bg = "white",
lwd=4)
# Setting the axes right ----
axis(1, at=xtics, labels=NULL, tick = TRUE)
axis(2, at=yrange, labels=yrange, las=1)
# FINISHED! ----
message ("Finished!")
生成的情节是这样的(你应该可以重现): 我还不能链接图像,所以这里是链接
所以,这暂时没关系。
但是,我想直观地突出直方图中的差异。当然我可以计算差异,这很好,因为我也需要,但我也想突出差异以显示有趣的区域。最终的图片应该是这样的
我不一定需要在正负差异之间进行颜色区分,但这会很好。我不知道如何遮蔽步骤数据之间的区域。
有人可以帮我弄这个吗?还有一件事,由于一些限制,我不允许使用太多的附加包。我正在使用“R 版本 3.1.1 (2014-07-10) -- “Sock it to Me””
非常感谢您!