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我正在尝试读取使用联系人选择器选择的联系人的电话号码。显示名称可以正常工作，但电话号码不能。代码：

//calling Contact Picker
public void CPick(View v){
        Intent intent=new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
        startActivityForResult(intent, PICK_CONTACT);
    }
    @Override
//Contact Picker here:
    protected void onActivityResult(int reqCode, int resultCode, Intent data){
        super.onActivityResult(reqCode,resultCode, data);

        if (reqCode==PICK_CONTACT){
            if(resultCode==AppCompatActivity.RESULT_OK){
                Uri contatctData=data.getData();
                Cursor c=getContentResolver().query(contatctData,null,null,null,null);
                if (c.moveToFirst()){
                    //String name=c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));
//Above line works Fine

                    String name=c.getString(c.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.Phone.NUMBER));
//Above line gives error on runtime "invalid column"
                    Toast.makeText(this,"U have picked:"+name,Toast.LENGTH_SHORT).show();



                }
            }

        }
    }

Anyhelp 将非常感激，因为我在任何地方都找不到相关的答案。

4

2 回答 2

1

试试这个方法：

private void retrieveContactNumber() {

  String contactNumber = null;

  // getting contacts ID
  Cursor cursorID = getContentResolver().query(uriContact,
        new String[]{ContactsContract.Contacts._ID},
        null, null, null);

  if (cursorID.moveToFirst()) {

    contactId = cursorID.getString(cursorID.getColumnIndex(ContactsContract.Contacts._ID));
  }

  cursorID.close();

  Log.d(TAG, "Contact ID: " + contactId);

  // Using the contact ID now we will get contact phone number
  Cursor cursorPhone = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
        new String[]{ContactsContract.CommonDataKinds.Phone.NUMBER},

        ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ? AND " +
                ContactsContract.CommonDataKinds.Phone.TYPE + " = " +
                ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE,

        new String[]{contactId}, null);

  if (cursorPhone.moveToFirst()) {
    contactNumber = cursorPhone.getString(cursorPhone.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
  }

  cursorPhone.close();

  Log.d(TAG, "Contact Phone Number: " + contactNumber);
}

您应该会在 logcat 中看到联系电话。

于 2017-11-13T19:35:27.710 回答
1

如果您想允许用户选择电话号码，最好的选择是使用 a PHONE-PICKERnot a CONTACT-PICKER：

Intent intent = new Intent(Intent.ACTION_PICK, CommonDataKinds.Phone.CONTENT_URI);
startActivityForResult(intent, PICK_PHONE);

...

protected void onActivityResult(int requestCode, int resultCode, Intent intent){
    if (requestCode == PICK_PHONE && resultCode == RESULT_OK){
        Uri phoneUri = intent.getData();
        Cursor cur = getContentResolver().query(phoneUri, new String[] { Phone.DISPLAY_NAME, Phone.NUMBER }, null, null, null);
        if (cur != null && cur.moveToFirst()){
            String name = cur.getString(0);
            String number = cur.getString(1);
            Log.d("PHONE-PICKER", "User picker: " + name + " - " + number);
            cur.close();
        }
    }
}
于 2017-11-13T19:19:43.383 回答